Given, Customers pay $4 to enter the pumpkin patch.
And also given, customers pay $3 per pound for the pumpkins.
Given, $y be the total cost and there are x pounds of pumpkins.
The cost for pumpkin per pound = $3.
Therefore, the cost for x pound pumpkins = $(3x)
As the total cost includes the payment for entering the patch also,
So the total cost y = 3x + 4
We have got the required equation.
The equation to model the total cost is y = 3x+4.
• So we know that.....
x represent bags of snack and y is bottles of water.
This equations shows the total amount and the cost of each water bottle and snack:
20.00 = 2.50x + 1.00y
Total: $20.00
Snack: $2.50
Water Bottle: $1.00
And this question shows the total items:
11 = x + y
Which there will be some snack + some water bottle = 11 items
—————————————————————
• Now I’m going to first solve for x, which is the amount of bags of snack.
I will use the equation, 11 = x + y.
(First, we’ll subtract y from both side, since we’re solving for x [UNDO])
11 = x + y
-y = - y
_______
11 - y = x —> so x is equal to 11 minus y.
—————————————————————
• Now we’re going to plug the 11 - y as x in the equation: 20.00 = 2.50x + 1.00y to solve for y.
20.00 = 2.50 (11 - y) + 1.00y
20.00 = 27.5 - 2.50y + 1.00y (Distributed)
20.00 = 27.5 - 1.50y (Combine like terms)
20.00 = 27.5 - 1.50y
-27.5 = -27.5 (Subtract -27.5 both side)
——————————
-7.5 = - 1.50y
-7.5 = -1.50y
—— ——— (Divide both side by -1.50)
- 1.50 = -1.50
5 = y
y is equals to 5, which means that there are 5 water bottles.
Now we know there are 11 items total and because there are 5 water bottles, there will be 6 bags of snacks. 11-5=6
—————————————————————
ANSWER:
They bought 6 bags of snacks! :)
We write an inequality:
This equation cannot be solved using trivial methods found in high-school classes, so we resort to graphical examination.
is a linear function while
is an exponential one (with limit zero as
approaches
). We see that
at approximately
and
.
Indeed, using a computer algebra system such as the ones on modern TI calculators and on many internet sites gives equality at
. By observing our graph, we see that
when
or
.
Answer:
"Vx: if x is a valid argument with true premises then x has a true conclusion"
In a symbol form
Vx ( P(x) ⇒ 2(x) )
Step-by-step explanation:
The Following statement in the form ∀x ______, if _______ then _______ is a valid argument and this because any valid argument with "true premises" has a "true conclusion" as well
we will rewrite this statement in a universal condition statement form
assume x is a valid argument with true premises
then the following holds true
p(x) : x is a valid argument with true premises
q(x) : x has true conclusion
applying universal conditional statement
"Vx, if x is a valid argument with true premises then x has a true conclusion"
In a symbol form
Vx ( P(x) ⇒ 2(x) )
