Answer:
You can draw three rectangles:
1- 28 * 1.
2- 14*2
3- 7*4
Step-by-step explanation:
We have a total area of 28. If we use only integer numbers, we can find all the divisors of 28. The possible rectangles will be organized with them, taking into account that the product of them, which means the area should be 28.
28 = 1*2*2*7
We can organize them as follows:
R1: 28 = 1*28
R2: 28 = 2*14
R3: 28 = 4*7
Finally, we can conclude that there are only three possibilities
1- 28 by 1.
2- 14 by 2
3- 7 by4
The perimeters will be:
Perimeter 1 = 2x1 + 2x28 = 58
Perimeter 2 = 2x2 + 2x14 = 32
Perimeter 3 = 2x4+2x7 = 22
Note that we can also write equations for circles<span>, </span>ellipses, and hyperbolas<span> in terms of cos and sin, and other </span>trigonometric functions<span>; there are examples of these ...</span>
The fraction is one whole aka one
2x+14=60(vertical)
2x=46
x=23
Step-by-step explanation:
7x + 8y = -12
8y=-12-7x
y=
