Answer:
1. The elephant should be given _ fl oz.
2. Every term in Pattern B is 1/4 the corresponding term in Pattern A.
3. 0.9 < 1.1
4. There are 7 tons in 14,000 pounds.
5. There are 17900 Milligrams in 17.9 grams.
Step-by-step explanation:
1. One ton is 2,000 pounds. So you would have to multiply 5.5 x 2,000.
5.5 x 2,000 = 11,000
Then you have to divide 11,000 by 250.
11,000/250 = 44
2. Every term in Pattern B is 4 times less than the term in Pattern A.
3. 0.9 is smaller than 1.1.
4. One ton is 2,000 pounds. 14,000/2,000 is 7 so this would mean that 14,000 pounds is 7 tons.
5. One gram is 1,000 milligrams, so you would have to multiply 17.9 by 1,000. This gives you 17900.
(27576km/hr)(24hr/day)(orbits/42600km)=orbits/day=15.53
So the station makes 15 FULL orbits per day
(27576km/h)(1000m/km)(h/3600s)=7660m/s
You have to start with the left triangle and find the side lengths. Since it is a 45-45-90, both sides are the same. Rule for this is hyp= sqrt2 * leg
Since hyp = 6sqrt2, the leg is 6.
The leg is also the hypotenuse of the triangle on the right side.
x is the side across from the hypotenuse and it is the short leg so x = (1/2)6
x = 3
Answer:
x=1, y=1. (1, 1). The answer is D).
Step-by-step explanation:
3x-5y=-2
4x-7y=-3
--------------
4(3x-5y)=4(-2)
-3(4x-7y)=-3(-3)
------------------------
12x-20y=-8
-12x+21y=9
--------------------
y=1
3x-5(1)=-2
3x-5=-2
3x=-2+5
3x=3
x=3/3
x=1
Answer:
B. 40 meters
Step-by-step explanation:
— Estimating
The rectangle enclosing the path has sides of length 9 m and 14 m, so its perimeter is 2(9+14) = 46 m. The distance covered will be shorter than that.
The distance from A to C is longer than the distance from D to C, so we know the distance will be longer than 2·14+9 = 37 m.
Only one answer choice fits in the range 37 < d < 46.
____
— Detailed calculation
The distance from B to C is the hypotenuse of a right triangle with sides 9 and 12. You will recognize that these side lengths are 3 times the side lengths of a 3-4-5 right triangle, so the hypotenuse distance is 3·5 = 15 meters.
The circuit length is ...
AB +BC +CD +DA = 2 + 15 + 14 + 9 = 40 . . . . meters
