Answer:
0.5
Step-by-step explanation:
Total space in the parking lot = 10
number of cars parked = p
number of empty parking spaces = e
There are the same number of cars parked in the parking lot as there are empty parking spaces.
This means,
Number of parked cars = number of empty parking spaces
p = e
If the number of parked cars and number of empty parking spaces = 10
p + e = 10
If p = 5
Then,
p + e = 10
5 + 5 = 10
Write a decimal to show the part of the parking lot that has empty parking spaces.
Empty parking space/total parking space
= 5/10
= 1/2
= 0.5
part of the parking lot that has empty parking spaces = 0.5
4y+5=4y-6 doesn't have a solution because you need to subtract 4y from both sides so you do 4y+5-4y=4y-6-4y so 5= -6 and then you subtract 5 from both sides which is 5-5=-6-5 and 0=-11.
Answer:
y + 1 = 8 (x + 7)
Step-by-step explanation:
point slope form is
y - y1 = m (x - x1)
So replace the y1 with the y point, and the x1 with the x point
y - (-1) = m (x - (-7) )
then replace the m with the slope
y - (-1) = 8 (x - (-7) )
now solve
y + 1 = 8 (x + 7)
Answer:
Where
and
We select a sample of n=16 and we are interested on the distribution of
, since the distribution for X is normal then we can conclude that the distribution for
is also normal and given by:

Because by definition:



And for this case we have this:


Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the IQ scores of a population, and for this case we know the distribution for X is given by:
Where
and
We select a sample of n=16 and we are interested on the distribution of
, since the distribution for X is normal then we can conclude that the distribution for
is also normal and given by:

Because by definition:



And for this case we have this:

