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Elis [28]
3 years ago
14

Enter an equation in point-slope form for the line.

Mathematics
1 answer:
Klio2033 [76]3 years ago
5 0

Answer:

y + 1 = 8 (x + 7)

Step-by-step explanation:

point slope form is

y - y1 = m (x - x1)

So replace the y1 with the y point, and the x1 with the x point

y - (-1) = m (x - (-7) )

then replace the m with the slope

y - (-1) = 8 (x - (-7) )

now solve

y + 1 = 8 (x + 7)

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What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps. put the answer in units²
AlladinOne [14]

Answer:

Therefore the Area of Rhombus ABCD is 36 unit².

Step-by-step explanation:

Given:

ABCD is a Rhombus

A = (-1,0)

B = (5,-3)

C = (-1,-6)

D = (-7 ,-3)

To Find:

Area of Rhombus ABCD = ?

Solution:

We know that Area of Rhombus is given as

\textrm{Area of Rhombus}=\dfrac{1}{2}\times d_{1}\times d_{2}

Where ,

d₁ and d₂ are the Diagonals.

We have,

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Using Distance Formula we get

l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}

Substituting coordinates A and C we get

l(AC) = \sqrt{((-1-(-1))^{2}+(-6-0)^{2} )}=\sqrt{36}\\l(AC)=6\ unit

Similarly for BD we have,

l(BD) = \sqrt{((5-(-7))^{2}+(-3-(-3))^{2} )}=\sqrt{144}\\l(BD)=12\ unit

Now Substituting AC and BD in Formula we get

\textrm{Area of Rhombus}=\dfrac{1}{2}\times AC\times BD

\textrm{Area of Rhombus}=\dfrac{1}{2}\times 6\times 12=36\ unit^{2}

Therefore the Area of Rhombus ABCD is 36 unit².

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What is the simplified form of each expression? (– h 4)5 A. – h 9 B. h 1 C. h 20 D. – h 20
Katena32 [7]
<span>(-h^4)^5 is -h^20 (-h^4)^5 = -h^4×5 = -h^20</span>
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Answer:              

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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