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Ratling [72]
3 years ago
10

Can someone please help?

Mathematics
1 answer:
Lelu [443]3 years ago
3 0

Answer:

He messed up on x + 2 = 5 (when he divided both sides by 3.)

He is first supposed to subtract 2 from both sides and you would get 13. Then you would divide both sides by 3 which would get you 4.33 repeating.

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Assume that adults have iq scores that are normally distributed with a mean of 100100 and a standard deviation of 15. find the t
anastassius [24]
The bell curve attached below shows the normal distribution of the data.

We are looking the value of X such as the area to its left gives the probability of 0.75

We first need the z-score which we can obtain by reading from the z-table (as shown in the second picture below)

The z-score is = 0.7734

Then we use the following formula to work out X
z-score = (X - Mean) ÷ Standard Deviation
0.7734 = (X - 100) ÷ 15
0.7734×15 = X - 100
11.601 = X - 100
X = 11.601 + 100
X = 111.601 ≈ 112 

Hence the third quartile is 112

4 0
3 years ago
1+4=5<br> 2+5=7<br> 3+6=21<br> 8+11=
Karolina [17]
This is a common math problem. There are two ways to answer this question but both will give you the same answer. There is a misconception that this can also equal 40. If someone posts that the answer is 40, please let me know and I will explain why that is not actually the answer.

1+4=5 2+5=7
3+6=21
8+11=

These equations are actually:

1*(4+1)=52*(5+1)=7
3*(6+1)=21
8*(11+1)=96

Therefore:
8+11 = 96
3 0
4 years ago
Read 2 more answers
Is the following relation a function? <br><br> Yes<br> Or<br> No
WITCHER [35]
Yes, that relation is a function. It has no repeating x values
6 0
3 years ago
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HELP ASAP 10 POINTS AND BRAINLIST
ollegr [7]

Step-by-step explanation:

hope it helps you...........

4 0
3 years ago
Answer this please! Thanks
Alex17521 [72]

Answer:

no solution

Step-by-step explanation:

The solution to a system of equations is at the point of intersection of the 2 lines.

The lines are parallel and never intersect.

Tgus the system has no solution

3 0
2 years ago
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