Question

Write the equation of the line for the following table of values.

Answer 1

Answer:

We conclude that the equation of the line is:

• $y = 5x + 1$

Step-by-step explanation:

The slope-intercept form of the line equation

$y = mx+b$

where

• m is the slope

• b is the y-intercept

Given the data table

x      -3 -5 -7 -9 -11

y      -16 -26 -36 -46 -56

From the table taking two points

• (-3, -16)

• (-5, -26)

Determining the slope between (-3, -16) and (-5, -26)

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$\left(x_1,\:y_1\right)=\left(-3,\:-16\right),\:\left(x_2,\:y_2\right)=\left(-5,\:-26\right)$

$m=\frac{-26-\left(-16\right)}{-5-\left(-3\right)}$

$m=5$

Thus, the slope of the line is:  m = 5

substituting m = 5 and (-3, -16) in the slope-intercept form of the line equation  to determine the y-intercept b

$y = mx+b$

-16 = 5(-3) + b

-16 = -15 + b

b = -16+15

b = 1

Thus, the y-intercept b = 1

now substituting m = 5 and b = 1 in the slope-intercept form of the line equation

$y = mx+b$

$y = 5x + 1$

Therefore, we conclude that the equation of the line is:

• $y = 5x + 1$