Let r and r+7 be Greg's rate for the first and second parts of his trip, respectively. Then: 210/r + 210/r+7=11 210(r+7)+210r=11(r²+7r) 420r+1470=11r²+77r 11r²-343r-1470=0 (11r+42)(r- 35)=0 r=-42/11 or 35 Choosing the positive value, we get 35 mph as his first speed, and 42 mph as his 2nd speed ☺☺☺☺