$-2(a-8)+6a=36 \\ \\ -2a + 16 + 6a = 36 \\ \\ 4a + 16 = 36 \\ \\ 4a = 36 - 16 \\ \\ 4a = 20 \\ \\ a = \frac{20}{4} \\ \\ a = 5 \\ \\$

The final result is: a = 5.

8 0

4 years ago

<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%2B%207xy%20%2B%2012%20%7By%7D%5E%7B2%7D%20" id="TexFormula1" title=

il63 [147K]

(x +3y)(x + 4y) tell me if you want me to tell you how I found it.

3 0

3 years ago

Lines l and m are parallel. If m∠3 = 3x + 11 degrees and m∠2 = 4x + 1 degrees, what is the measure of ∠7? 41 degrees 139 degrees

kipiarov [429]

Answer:

m<7 = 139°

Step-by-step explanation:

Given:

m<3 = (3x + 11)°

m<2 = (4x + 1)°

Required:

m<7 = ?

SOLUTION:

Given that l and m are parallel lines, m<3 and m<2 are alternate interior angles.

Alternate interior angles are congruent. Therefore:

m<3 = m<2

$3x + 11 = 4x + 1$ (substitution)

Solve for x

$3x + 11 - 4x = 4x + 1 - 4x$

$-x + 11 = 1$

$-x + 11 - 11 = 1 - 11$

$-x = -10$

Divide both sides by -1

$x = 10$

Find m<2:

m<2 = (4x + 1)

Plug in the value of x

m<2 = 4(10) + 1 = 40 + 1

m<2 = 41°

Find m<7:

m<2 + m<7 = 180° (consecutive interior angles are supplementary)

41° + m<7 = 180° (substitution)

m<7 = 180 - 41 (subtracting 41 from each side)

m<7 = 139°

3 0

3 years ago