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3 years ago

Question 1

Mathematics

1 answer:

Pavlova-9 [17]3 years ago

5 0

Answer:

You'll need to look at the attached formula.

Annual Payout = 500,000 * .12 * (1.12)^15 / [(1.12)^15 -1]

Annual Payout = 500,000 * .12 * 5.4735657593 / [ 5.4735657593 -1]

Annual Payout = 500,000 * .12 * 5.4735657593 / [4.4735657593]

Annual Payout = 60,000 * 5.4735657593 / [4.4735657593]

Annual Payout = 73,412.12

Source: http://www.1728.org/annupay.htm

That's a LOT of calculating :-)

Step-by-step explanation:

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The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

I am Lyosha [343]

Answer:

(a) The proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b) The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

Step-by-step explanation:

Let X = number of students who read above the eighth grade level.

(a)

A sample of n = 269 students are selected. Of these 269 students, X = 224 students who can read above the eighth grade level.

Compute the proportion of students who can read above the eighth grade level as follows:

$\hat p=\frac{X}{n}=\frac{224}{269}=0.8327$

The proportion of students who can read above the eighth grade level is 0.8327.

Compute the proportion of tenth graders reading at or below the eighth grade level as follows:

$1-\hat p=1-0.8327$

$=0.1673$

Thus, the proportion of tenth graders reading at or below the eighth grade level is 0.1673.

(b)

the information provided is:

n = 709

X = 546

Compute the sample proportion of tenth graders reading at or below the eighth grade level as follows:

$\hat q=1-\hat p$

$=1-\frac{X}{n}$

$=1-\frac{546}{709}$

$=0.2299\\\approx 0.229$

The critical value of z for 95% confidence interval is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for the population proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.229\pm 1.96\times \sqrt{\frac{0.229(1-0.229)}{709}}\\=0.229\pm 0.03136\\=(0.19764, 0.26036)\\\approx (0.198, 0.260)$

Thus, the 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.198, 0.260).

5 0

3 years ago

Plz plz help I've been stuck on this since yesterday

Vanyuwa [196]

y=ax+b

then

-9= -9a+b

0= -6a+b

a=3 and b=18

y=3x+18

7 0

3 years ago

Read 2 more answers

Josie is training for a race.The ratio of the number of minutes she runs to the number of miles she runs is 24 to 3 she plans to

Fiesta28 [93]

Answer:

80 minutes

Step-by-step explanation:

She runs an 8 minute mile (which you can do by dividing 24/3), then how long will it take her to run 10 miles?

All you have to do from there is multiply 8x10, which gives you 80.

It'll take 80 minutes of 1:20 hours

7 0

2 years ago

Read 2 more answers

What are the solutions of the equation y = negative 2 x squared + 9 x minus 4 shown in the graph below?

aleksandr82 [10.1K]

Answer:the answer c

Step-by-step explanation:

3 0

2 years ago

How many sets of two or more consecutive positive integers can be added to obtain a sum of 1800?

Nataliya [291]

Answer:

n = 60

Step-by-step explanation:

GIVEN DATA:

Total sum of consecutive number is 1800

sum of n number is given as

$sum = \frac{ n(n+1)}{2}$

where n is positive number and belong to natural number i.e 1,2,3,4,...

from the data given we have $1800 = \frac{n(n+1)}{2}$

solving for n we get

[/tex]n^2 + n -3600 = 0[/tex]

n = 59.5, -60.5

therefore n = 60

4 0

3 years ago