Answer:
Twelve tickets cost $30 --> True
Thirty tickets cost $12 --> False
Each additional costs $2.50 --> True
The table is a partial rep --> True
ordered pairs --> False
Step-by-step explanation:
Twelve tickets cost $30 --> True, you can literally see that in the table
Thirty tickets cost $12 --> False, 30 is not in the table so you don't have that information. Besides, $12 is an unlikely low value for so many tickets.
Each additional costs $2.50 --> True, you can see the difference in the TotalCost column to be consistently 2.50.
The table is a partial rep --> True, values below 11 are not shown for example.
ordered pairs --> False --> Then the x value should be first, e.g., (11, 27.50), since the cost y is a function of the number x.
We Know, volume of cube, m³ = 4913
m = ∛4913
m = 17
So, your final answer is 17
Hope this helps!
You can get all the terms on one side, and then solve for x by any means:

Factor out a -2:

Factor this equation:

I will use the AC method. To use it, first multiply a and c (in ax^2 + bx +c):

Now, look for two numbers that multiply to -12 and add to -11. Obviously these numbers are -12 and 1. (-12*1 = -12 and -12+1 = -11). Now, because of rules, you set it up in a Punnett square:
4x^2 -12x
x -3
Now, we find common factors of the terms in rows:
_x_______-3__
4x| 4x^2 -12x
1 | x -3
So, you can use this to write an equivalent expression to the quadratic given:

Now, we known the factors are (solve for x):
3 and -1/4.
Answer:
The n-th term of this sequence appears to be
3
n
−
1
,
n
≥
1
.
Step-by-step explanation:
These are powers of
3
ordered from
3
0
=
1
to
3
a
(for an integer
a
≥
1
). However, the first convenient value for
n
is
1
, not
0
(imagine saying the 0th term of a sequence). Because of that, since the first term is actually
3
0
, we need to start from the first term (
n
=
1
) being
3
1
−
1
. The next is
3
2
−
1
,
3
3
−
1
...
3
n
−
1
.
1. 34 * 87= 238
2. 65 * 79 = 585 + 4550= 5135
3. 96 * 24= 384+1920=2304
4. 82*68=656+4920=5576
5. 531*47=3717+21240=24957
6. 246*83=738+19680=20418
7. Find the square root of 2025 and it is 45