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noname [10]
3 years ago
10

Safety by-laws state that for a ladder to be stable, the angle the base of the ladder makes with the ground should be between 70

° and 80'. A safety inspector at a construction site notices a painter on a 10-m ladder that is leaning against a wall. The base of the ladder is 1.5 m away from the wall. Does the inspector have cause to be concerned? Explain.​
Mathematics
1 answer:
tatiyna3 years ago
5 0

Cos(angle) = adjacent/hypotenuse

Cos(angle) = 1.5/10

Angle = arccos(1.5/10)

Angle = 81.37 degrees

Although the angle is close, it is over the 80 degrees, so the inspector should be concerned.

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A lot of 9 components contains 3 that are defective. Two components are drawn at random and tested. Let be the event that the fi
kirza4 [7]

Answer:

Probabilty of first component drawn defective= 0.1161

Probability of second component drawn defective= 0.1560

Step-by-step explanation:

Total component = 9

Defective component= 3

Non-defective component= 6

Probability of defective= 3/9

= 0.3333

Probabilty of non defective= 1-0.3333

= 0.6666

Probabilty of first component drawn is defective

= 9C1(0.333)¹(0.6666)^8

= 9(0.3333)(0.0387)

= 0.1161

Probabilty of second component is defective

= 8C1(0.3333)¹(0.6666)^7

= 8(0.3333)(0.0585)

= 0.1560

7 0
3 years ago
F a gambler rolls two dice and gets the sum of 7, he wins $20. if he gets a sum of 4, he wins $40. the cost of playing is $14. w
DaniilM [7]
The expectation of this game is that the house (casino) takes in roughly $3.83 every time someone plays, and after enough plays, they will typically always win. 

We can determine this case by looking at all of the possibilities and how much you can win or lose off of each. There are 36 total cases for what can happen when we roll the dice. Of those 36 cases, 9 of them produce positive winnings and 27 of them produce losses. 

To calculate the winnings, we need to look at what type they are. 6 of them will be 7's which earn the gambler $20. 3 of them would be 4's, which earns the gambler $40. 

6($20) + 3($40) 
$120 + $120
$240

Then we look at the losses. This is easier to calculate since every time the gambler loses, he losses exactly $14. There are 27 of these instances. 

27($14) 
$378

Now we can look at the average loss per game by subtracting the losses from the gains and finding the average. 

(Winnings - losses)/options
($240 - 378)/36
$3.83
3 0
3 years ago
Kathryn’s total assets are $57,219. Her total liabilities are $43,244. What is her net worth? A. $14,198 B. $1397 C. $13,975 D.
zepelin [54]
If your going to add then it would be
57,219 + 43,244 = 100,463 D.

I your going to subtract then it would be
57,219 - 43,244 = 13,975 C.

ello
3 0
3 years ago
PLEASE HELP ASAP!!
Furkat [3]
For school A: 2, 2, 3, 7, 10,10,14, 17, 22
School A : 2,2,3,7,10,10,14,17,22
Part A: (2 + 3) / 2 = 5/2 = 2.5
The Median is 10
(14 + 17) / 2 = 31/2 = 15.5
The IQR Is Q3 - Q1 = 15.5 - 2.5 = 13

For School B: <span>Nope, not symmetrical. The space between the medians should be the same number.

Hope this Helps. I can explain more if you have an comments.
</span>

4 0
3 years ago
A basketball player averaged 20 points a game over the course of six games. His
Nataly_w [17]
<h3>Hello There!!</h3>

<h3><u>Given,</u></h3>

Average Points= 20

No. of games = 6

Total points= 20×6=120

So, Sum of Score of five games= 23+18+16+24+27= 108

Therefore, Score in 6th game= 120-108= 12

<h3>Hope this helps</h3>
3 0
2 years ago
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