Let A( t , f( t ) ) be the point(s) at which the graph of the function has a horizontal tangent => f ' ( t ) = 0.
But, f ' ( x ) = [ ( x^2 ) ' * ( x - 1 ) - ( x^2 ) * ( x - 1 )' ] / ( x - 1 )^2 =>
f ' ( x ) = [ 2x( x - 1 ) - ( x^2 ) * 1 ] / ( x - 1 )^2 => f ' ( x ) = ( x^2 - 2x ) / ( x - 1 )^2;
f ' ( t ) = 0 <=> t^2 - 2t = 0 <=> t * ( t - 2 ) = 0 <=> t = 0 or t = 2 => f ( 0 ) = 0; f ( 2 ) = 4 => A 1 ( 0 , 0 ) and A 2 ( 2 , 4 ).
Answer:
C
Step-by-step explanation:
(3,15) and (4,12)
Answer:
y = 50
Step-by-step explanation:
All triangle angles add up to 180 degrees.
To set this equation up, you need to add everything given in the triangle and set it equal to 180:
y + y + 80 = 180
<em><u>Add like terms:</u></em>
2y + 80 = 180
<u><em>Subtract 80 from both sides:</em></u>
2y + 80 = 180
- 80 - 80
___________
2y = 100
<u><em>Divide both sides by 2:</em></u>
y = 50
<u><em>If you're unsure, you can plug in the 50 for y:</em></u>
y + y + 80 = 180
50 + 50 + 80 = 180
100 + 80 = 180
180 = 180
Answer:
y = -(1/2)x + 4
Step-by-step explanation:
Use the standard form on an equation: y = mx + b
A line that is perpendicular has a slope that is the opposite reciprocal of the other line. We also have a point (x, y) that is on the line, so our equation begins as..
1 = -(1/2)(6) + b We must solve for b ( -1/2 is the opposite reciprocal of 2)
1 = -3 + b
4 = b
so our equation is
y = -(1/2)x + 4
So x + y = 45, and 4x + 5y = 195. Get y by itself. Subtract x from both sides in the first equation to get y = 45 -x, and subtract 4x from the second equation to get 5y = 195 - 4x. Divide by 5 to both sides to get y = 39 - 4/5x. 39 - 4/5x = 45 - x. Add x to both sides to get 39 - 1/5x = 45. Subtract 39 from both sides to get -1/5x = 6. Divide by -1/5 to get x = -30, or 30. In the first equation, do 30 + y = 45. Subtract 30 from both sides to get y = 15. Check. 4(30) + 15(5) = 195, or 120 + 75 = 195.
