The order of rotational symmetry of a kite is 1
You question implies simple subtraction is needed:
28-8=20
Answer:
Step-by-step explanation:
for IV you do 40^2+30^2=c, or 1600+ 900=c. c= 2500 and unsquare that you get 50
Answer:
73
Step-by-step explanation:
Since DA is the diameter, this means that you can divide the circle into two half-circles. You will solve with the right half-circle. A half-circle has a 180 total degrees. Add up the values given and solve for x.
(2x) + (7x - 4) + (85) = 180
2x + 7x - 4 + 85 = 180
9x - 4 + 85 = 180
9x + 81 = 180
9x = 99
x = 11
Now that you have the value of x, solve for m∠CZB.
m∠CZB = 7x - 4
m∠CZB = 7(11) - 4
m∠CZB = 77 - 4
m∠CZB = 73
Answer:
A. Orthocenter
Step-by-step explanation:
In the given triangle, ΔWKS, the drawing shown the construction of a perpendicular line to the side KS that pass through the vertex <em>W </em>of ΔWKS. Therefore, the completed construction gives an altitude of the triangle ΔWKS
Repeating the same procedure from the vertex <em>S</em> to construct the perpendicular line (altitude) to the side WK, and from the vertex <em>K</em> the perpendicular line (altitude) to the side WS gives the three altitudes of the triangle
The point of intersection (the point of concurrency) of the three altitudes is the <em>orthocenter </em>of the triangle and the drawing would therefore be a step in finding the <em>orthocenter </em>of a triangle.
