Answer:
The value at the end of year 2 is $4400.
Step-by-step explanation:
The best approach here is to determine the expression for the line depreciation and then calculate the depreciation value at x = 2 years.
A line is given by

where m is the slope and b the bias (aka y-intercept). You can determine both directly from what is given. The slope is change in y divided by change in x. We know that over 5 years the car loses (500-7000)=-6500 in value. So, the slope is m=-6500/5 (note the negative sign). At time 0, the y-intercept is 7000, since that is the initial value (at year 0). So our line function is fully identified:

and gives you the value of the car in any given year. To answer the question, we now plug in 2 as value of x:

Answer:
Step-by-step explanation:
A hole is an input value that makes both numerator and denominator equal to zero.
<u>Let's factorize the numerator and denominator:</u>
- 3x² - 108 = 3(x² - 36) = 3(x + 6)(x - 6)
- x² + 2x - 24 = x² + 6x - 4x - 24 = x(x + 6) - 4(x + 6) = (x - 4)(x + 6)
<u>We have same factor of x + 6:</u>
- x + 6 = 0
- x = - 6 is a hole
0.0166 because it’s bigger than all other numbers
The standard form is 21x-y-7=0
1\5 pound of trail mix because 1 pound divided to\by 5 people is 1\5.
So, each person gets 1\5 pound trail mix