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Rzqust [24]
3 years ago
7

How to solve the problem, and complete answer

Mathematics
1 answer:
rusak2 [61]3 years ago
5 0
Notice the picture below

thus, solve for "y"

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What are the solution(s) to the quadratic equation 40 - x2 = 0?
Zanzabum

Answer:

  x=\pm2\sqrt{10}

Step-by-step explanation:

You want to solve ...

  40 -x^2=0\\\\40=x^2\qquad\text{add $x^2$}\\\\\pm\sqrt{40}=x\qquad\text{take the square root}\\\\\boxed{x=\pm2\sqrt{10}}\qquad\text{simplify}

5 0
3 years ago
Please answer the picture below!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Temka [501]

Surface area of the base = 4^2 = 16 units^2.

Area of each triangular side = 1/2 * 4 * 3 = 6 unts^2

Total surface area of the pyramid = 16 + 4 * 6 = 40 unit^2 (answer)

7 0
4 years ago
Read 2 more answers
If f(x) = 4x² – 3x + 8, then f(-2) =
Citrus2011 [14]

Answer: 30

Step-by-step explanation:

16+6+18

7 0
3 years ago
A. 8/17<br> B. 15/17<br> C. 15/8<br> D. 8/15
Vlada [557]

Answer:

A)  8/17

Step-by-step explanation:

cos = adj/hyp

In this problem the unknown angle has a hypotenuse pf 17, 15 as opposite, and 8 as adjacent

8 0
2 years ago
If copies cost .08 per copy but you buy a fuscount card for 7.50 and the copies are .05 how many copies will make it worth the d
timurjin [86]

Answer:

<u>The number of copies that will make it worth the discount card is 250.</u>

Step-by-step explanation:

1. Let's review the information provided to answer the question correctly:

Cost per copy without discount = US$ 0.08

Cost per copy with discount = US$ 0.05

Cost of discount card = US$ 7.50

2. How many copies will make it worth the discount card?

For finding out this number of copies, we will use the following equation:

x = Number of copies that will make it worth the discount card

0.08x = 0.05x + 7.50

0.03x = 7.50 (Like terms)

3x = 750 (Multiplying by 100 at both sides)

x = 250 (Dividing by 3 at both sides)

<u>The number of copies that will make it worth the discount card is 250.</u>

Note: Same answer to question 14127203, answered by me today.

7 0
3 years ago
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