Please please help !!

Advanced Placement (AP)

1 answer:

LekaFEV [45]3 years ago

5 0

I believe the answer is 2 and 3

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The equations of the tangent to the curve y=xsinx at the point (pi/2,pi/2) is

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$\frac{d}{dx} xsin(x)$

Next use product rule (I recommend watching videos if you're confused):

$= [sin(x)] + [x*cos(x)]$

Next substitute you x-value (π/2) into your derivative:

$= [sin( \frac{ \pi}{2} )] +[ \frac{\pi}{2}*cos( \frac{\pi}{2})]$
$= 1 + \frac{\pi}{2} *0$
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So our slope at π/2 is 1. Next we use our slope-form and substitute our given value and solve for y-intercept (algebra-stuff)

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So we get our equation:

$y = x$

So our answer is E

Feel free to ask any questions.
Hopes this helps!

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