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kolezko [41]
3 years ago
14

Select the correct answer.

Advanced Placement (AP)
1 answer:
denis-greek [22]3 years ago
5 0

Answer:

D

Explanation:

i feeling better today and I will be there at like my name I to the other email with the link to the largest side and the recording of the app and it doesn't look like my name is or new hdd to me and I'll be there at like my new one and it was planned on going through the same thing with the link when we get back from lunch

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What mass of iron (II) sulfide will be produced if 9.68 g of iron reacts with 6.28 g of sulfur
Naya [18.7K]

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15.96 g

Explanation:

9.68+6.28=15.96

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How to do the question
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The answer is 27/4    Decimal Form: 6.75

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Regina struggles with reading long passages and feels like no matter how hard she tries she will not understand them, so she ski
tresset_1 [31]

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U.S. foreign policy shifted away from (BLANK) to international involvement.
suter [353]

Answer:

Isolationism

Explanation:

In the 19th century, the United States under the administration of George Washington established a policy to isolate itself from intervening in foreign wars. There were deliberations as to whether the United States will join the League of Nations and interfere in wars. This policy was a result of the economic crisis faced by the United States at that time and there was a need to focus on the problems than getting involved in foreign affairs. Thomas Woodrow Wilson assuming power as the President of the United States, also maintained that stance as he urged the United States not to involve in wars.

Wilson changed his mind after he realized the war in Europe will most likely extend to the Atlantic Ocean. The number of people killed in the war also propelled the intervention of the United States. Its strong alliance in maintaining peace and stability in all states was also a key factor. With this intervention in the World War, the United States assumed the status of World power.

5 0
3 years ago
The regions bounded by the graphs of y=x2 and y=sin2x are shaded in the figure above. What is the sum of the areas of the shaded
Alex Ar [27]

Answer:

The sum of the area of the shaded regions = 0.248685

Explanation:

The sum of the area of the shaded region is given as follows;

The point of intersection of the graphs are;

y = x/2

y = sin²x

∴ At the intersection, x/2 = sin²x

sinx = √(x/2)

Using Microsoft Excel, or Wolfram Alpha, we have that the possible solutions to the above equation are;

x = 0, x ≈ 0.55 or x ≈ 1.85

The area under the line y = x/2, between the points x = 0 and x ≈ 0.55, A₁, is given as follows

1/2 × (0.55)×0.55/2 ≈ 0.075625

The area under the line y = sin²x, between the points x = 0 and x ≈ 0.55, A₂, is given using as follows;

\int\limits {sin^n(x)} \, dx = -\dfrac{1}{n} sin^{n-1}(x) \cdot cos(x) + \dfrac{n-1}{n} \int\limits {sin^{n-2}(x)} \, dx

Therefore;

A_2 = \int\limits^{0.55}_0 {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_0 ^{0.55}

∴ A₂ =1/2 × ((0.55 - sin(0.55)×cos(0.55)) - (0 - sin(0)×cos(0)) ≈ 0.0522

The shaded area, A_{1 shaded} = A₁ - A₂ = 0.075625 - 0.0522 ≈ 0.023425

Similarly, we have, between points 0.55 and 1.85

A₃ = 1/2 × (1.85 - 0.55) × 1/2 × (1.85 - 0.55) + (1.85 - 0.55) × 0.55/2 = 0.78

For y = sin²x, we have;

A_4 = \int\limits^{1.85}_{0.55} {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_{0.55} ^{1.85} \approx 1.00526

The shaded area, A_{2 shaded} = A₄ - A₃ = 1.00526 - 0.78 ≈ 0.22526

The sum of the area of the shaded regions, ∑A = A_{1 shaded} + A_{2 shaded}

∴ A = 0.023425 + 0.22526 = 0.248685

The sum of the area of the shaded regions, ∑A = 0.248685

8 0
3 years ago
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