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vichka [17]
3 years ago
14

Please help me this math is timed it's in Algebra. I'll double points. 1. (x^-2 y^3)^-1 2. (5x^3/y^2)^4 3. 36x^3y^-3/6x^5y^-6 Ma

ybe more, but right now that's it.
Mathematics
1 answer:
LenaWriter [7]3 years ago
8 0

Answer:

1. \frac{x^2}{y^3}

2. \frac{625x^{12}}{y^8}

3. \frac{6}{x^2y^9}

Step-by-step explanation:

Remember, when you exponent an exponent, you multiply the powers.

When you multiply exponents, you add them.

When you divide exponents, you subtract them.

1.

Step 1: Multiply exponents

x^2y^{-3}

Step 2: Move y^{-3} to the denominator

\frac{x^2}{y^3}

2.

Step 1: Multiply exponents

\frac{5^4(x^{3})^{4}}{(y^2)^4}

Step 2: Power

\frac{625x^{12}}{y^8}

3.

Step 1: Simplify

\frac{6x^3y^{-3}}{x^5y^6}

Step 2: Remove terms

\frac{6y^{-3}}{x^2y^6}

Step 3: Move y^{-3} to the denominator

\frac{6}{x^2y^6y^3}

Step 4: Combine like terms

\frac{6}{x^2y^9}

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Select the center and scale factor of the dialation that maps segment GH on to G'H'
Schach [20]

Answer: The center is E (0,0) because point G and point H' are three points away from (0,0).  The scale factor is C (5/3) because line segment GH is 3 units long and line segment G'H' is 5 units long. You would divide the transformed figure with the original figure.


Step-by-step explanation:


6 0
3 years ago
¿De que cantidad es L.531.55 el 125%?
Natali [406]

Answer:

Step-by-step explanation:

531.55 = 125% of x = 1.25x

x = 531.55/1.25 = 425.24

4 0
3 years ago
6. Let E, F, G be three events. Find expressions for the events that of E, F, G a. only E occurs; b. both E and G but not F occu
marta [7]

Answer:

a.) only E occurs :

E((FUG)')

b.) both E and G but not F

EG(F')

C.) Atleast one of the events :

(E U G U F)

d.) Atleast two of the events

(EG U EF U GF)

E.) all three occurs

(EGF)

F.) none of the events occur :

(E U G U F)'

G.) At most one of the events occur

(EG U EF U GF)'

H.) at most two of them occur

(E' U G' U F')

I.) exactly two of them occur;

(EG U EF U GF) * (EGF)'

j. at most three of them occur.

EFG U (EFG)'

Step-by-step explanation:

Events = {E, F, G}

a.) only E occurs :

E((FUG)') ; E and not F or G

b.) both E and G but not F

EG(F') ; both E and G and not F

C.) Atleast one of the events :

(E U G U F) ; Either E or F or G

d.) Atleast two of the events

(EG U EF U GF) ; Either EG or EF or GF occurs

E.) all three occurs

(EGF) ; All three events, E, G and F occurs

F.) none of the events occur :

(E U G U F)' ; Neither E, G nor F occurs

G.) At most one of the events occur

(EG U EF U GF)' ; complement of atleast two) at most one

H.) at most two of them occur

(E' U G' U F') ; Either E , F or G does not occur

I.) exactly two of them occur;

(EG U EF U GF) * (EGF)' ; Exactly two events occurs and all three events Do not occur

j. at most three of them occur.

EFG U (EFG)' ; All three events occur union all three events do not occur

6 0
3 years ago
I need the answer right away
PtichkaEL [24]

Answer:

It's B

Step-by-step explanation:

-a +5a-a =3a

+4-6=-2

= 3a-2

7 0
3 years ago
Read 2 more answers
A gardener plants two types of trees in a park:
slega [8]

Answer:

8 years

Step-by-step explanation:

Lets write an equation for Type A

The initial value is 5 ft  and the slope 12 inches

We need to have the same units, so lets change 5 ft to inches

5 ft * 12 inches / ft = 60 inches

y = mx+b

y = 12 x + 60

Lets write an equation for Type B

The initial value is 3 ft  and the slope 15 inches

We need to have the same units, so lets change 3 ft to inches

3 ft * 12 inches / ft = 36 inches

y = mx+b

y = 15 x + 36

We want to know when y is the same value.  We can set the equations equal.

12x + 60 = 15x+36

Subtract 12 x from each side

12x-12x+60 = 15x-12x +36

60 =3x+36

Subtract 36 from each side

60-36 = 3x+36-36

24 = 3x

Divide each side by 3

24/3 = 3x/3

8 =x

It will take 8 years for the trees to be the same height

7 0
3 years ago
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