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3 years ago

A store pays $35 for a fish tank. The markup is 20%. What is the selling price

Mathematics

2 answers:

snow_lady [41]3 years ago

8 0

The selling price is $42

iris [78.8K]3 years ago

6 0

$\\
\text{The store pays }\$35 \text{ for a fish tank.}\\
\text{and the markup is }20\% \text{ of }\$35\\
\\
\text{so first we find the markup as}\\
\\
=20\% \text{ of }\$35\\
\\
=0.20\times 35\\
\\
=7\\
\\
\text{hence the selling price of fish tank}=\text{Cost of store + Markup}\\
\\
\Rightarrow \text{selling price}=35+7\\
\\
\Rightarrow \text{selling price}=42$

Hence the selling price of the fish tank is $42

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Tickets for admission to a high school football game cost $3 for students and $5 for adults. During 1 game, $2995 was collected

Sveta_85 [38]

Answer:

Number of student tickets = 325

Number of adult tickets = 404

Step-by-step explanation:

Let,

x be the number of student tickets

y be the number of adult tickets

According to given statement;

x+y=729 Eqn 1

3x+5y=2995 Eqn 2

Multiplying Eqn 1 by 3

3(x+y=729)

3x+3y=2187 Eqn 3

Subtracting Eqn 3 from Eqn 2

(3x+5y)-(3x+3y)=2995-2187

3x+5y-3x-3y=808

2y=808

Dividing both sides by 2

$\frac{2y}{2}=\frac{808}{2}\\y=404$

Putting y=404 in Eqn 1

x+404=729

x=729-404

x=325

Hence,

Number of student tickets = 325

Number of adult tickets = 404

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mrs_skeptik [129]

Answer:

Answer choice C

Step-by-step explanation:

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Find T, N, and B for the curve at the indicated point. [HINT: After finding T', plug in the specific value for t before computin

lyudmila [28]

Answer:

Step-by-step explanation:

Given that

$r(t) = (t,t,e^t)$

To find tangent, normal and binormal vectors at (0,0,1)

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$r'(t) = (1,1,e^t)\\$

At the particular point, r'(t) = (1,1,e)

Tangent vector = $\frac{r'(t)}{||r'(t)||} \\=\frac{(1,1,e)}{\sqrt{1+1+e^2} } \\=\frac{(1,1,e)}{\sqrt{2+e^2} }$

ii) Normal vector

T'(t) = $(0,0,e^t)\\$

At that point T'(t) = (0,0,e)/e = (0,0,1)

iii) Binormal

B(t) = TX N

= $\left[\begin{array}{ccc}i&j&k\\1&1&e^t\\0&0&e^t\end{array}\right] \\= e^t(i-j)$

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4 years ago

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Sholpan [36]

Answer: Choice D

b greater-than 3 and StartFraction 2 over 15 EndFraction

In other words,

b > 3 & 2/15

$b > 3\frac{2}{15}\\\\$

========================================================

Explanation:

Let's convert the mixed number 2 & 3/5 into an improper fraction.

We'll use the rule

a & b/c = (a*c + b)/c

In this case, a = 2, b = 3, c = 5

So,

a & b/c = (a*c + b)/c

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2 & 3/5 = (10 + 3)/5

2 & 3/5 = 13/5

The inequality $2 \frac{3}{5} < b - \frac{8}{15}\\\\$ is the same as $\frac{13}{5} < b - \frac{8}{15}\\\\$

---------------------

Let's multiply both sides by 15 to clear out the fractions

$\frac{13}{5} < b - \frac{8}{15}\\\\15*\frac{13}{5} < 15*\left(b - \frac{8}{15}\right)\\\\39 < 15b-8\\\\$

---------------------

Now isolate the variable b

$39 < 15b-8\\\\15b-8 > 39\\\\15b > 39+8\\\\15b > 47\\\\b > \frac{47}{15}\\\\b > \frac{45+2}{15}\\\\b > \frac{45}{15}+\frac{2}{15}\\\\b > 3+\frac{2}{15}\\\\b > 3\frac{2}{15}\\\\$

Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how

47/15 = 3 remainder 2

The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.

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3 years ago