3 years ago

HELP ASAP WILL GIVE BRAINLIEST

Mathematics

1 answer:

leva [86]3 years ago

3 0

Answer:

$y=7x-7$

Step-by-step explanation:

Slant asymptote: It is a non-vertical and non-horizontal line graph approaches this line but the graph never crosses it. It exists when degree of numerator is greater than that of denominator. It can be calculated by dividing numerator by denominator.

$Let\ the\ function\ f(x)=\frac{7x^3+4x-2}{x^2+x-5}\\\\Then\ find\ oblique\ asymptote=(x^2+x-5)(7x-7)+(46x-37)\\\\The\ oblique\ asymptote\ (y)=7x-7$

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