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d1i1m1o1n [39]
3 years ago
8

HELP ASAP WILL GIVE BRAINLIEST

Mathematics
1 answer:
leva [86]3 years ago
3 0

Answer:

y=7x-7

Step-by-step explanation:

Slant asymptote: It is a non-vertical and non-horizontal line graph approaches this line but the graph never crosses it. It exists when degree of numerator is greater than that of denominator. It can be calculated by dividing numerator by denominator.

Let\ the\ function\ f(x)=\frac{7x^3+4x-2}{x^2+x-5}\\\\Then\ find\ oblique\ asymptote=(x^2+x-5)(7x-7)+(46x-37)\\\\The\ oblique\ asymptote\ (y)=7x-7

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X>-1/3, the graph would be filled everything to the right of -1/3 on the x axis
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12 = ____% of 160? Thank you!
beks73 [17]
7.5% of 160.

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3 years ago
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What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know
xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true  positive rate).

⇒ P(+/S) =<u> P(+ ∩ S)  </u>

                    P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly  healthy (true negative rate)

⇒ P(-/H) =<u> P(- ∩ H)  </u>

                   P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= <u> P(+ ∩ S)  </u>

                P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) =<u> P(+ ∩ S) </u>

                 P(S)

P(+/S)* P(S)  = P(+ ∩ S)  

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)=  P(+ ∩ S) +  P(+ ∩ H)

Now we know that 1% of the population has the blood sickness, wich means that 99% of the population doesn't have it, symbolically: P(H)= 0.99

Then you can clear the value of P(+ ∩ H):

P(+/H) =<u> P(+ ∩ H) </u>

                 P(H)

P(+/H)*P(H)  = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)=  P(+ ∩ S) +  P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= <u> P(+ ∩ S)  </u> =<u> 0.0095 </u>= 0.32

                P(+)        0.0293

I hope it helps!

                 

                 

6 0
3 years ago
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Dafna11 [192]

Answer:

Hey, idk the answer but are you taking alebra 1 on flvs? if so what were the questioned asked because i have a DBA tomorrow and i need the questions so i know what to expect.. i'm sorry i don't have the answer

Step-by-step explanation:

7 0
3 years ago
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