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topjm [15]
3 years ago
12

Plz help I have to do a test tomorrow on this!

Mathematics
1 answer:
melomori [17]3 years ago
4 0

What do you need help with? Nothing is showing :/

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What is the function for the table below? (Explain)
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12 because I took the test

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3 years ago
Match the following items.
IgorLugansk [536]

Answer:

#1 is 3x + 4 =-17 #2 is 3x =-21 #3 is x = -7 #4 is 2x + x +4 = -17

Step-by-step explanation:

#1 gives you the problem ready to be worked out. #2 all you need to do to finish it is divide both sides by 3. #3 the answer is already there. #4 You need to combine the like terms then solve the problem.

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3 more than twice a number is 17 (how do I translate into a equation?)
makkiz [27]
U need to convert it
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Please help me this is my last question
soldier1979 [14.2K]

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Step-by-step explanation:

6 0
2 years ago
A drug company is considering marketing a new local anesthetic. The effective time of the anesthetic the drug company is current
vladimir2022 [97]

Answer:

z=\frac{7.1-7.4}{\frac{1.2}{\sqrt{36}}}=-1.5  

Since is a left sided test the p value would be:  

p_v =P(z  

Comparing the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly lower than 7.4 minutes at 10% of significance

Step-by-step explanation:

Data given and notation  

\bar X=7.1 represent the sample mean    

\sigma=1.2 represent the population standard deviation

n=36 sample size  

\mu_o =7.4 represent the value that we want to test  

\alpha=0.1 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean i lower than 7.4, the system of hypothesis would be:  

Null hypothesis:\mu \geq 7.4  

Alternative hypothesis:\mu < 7.4  

The statistic is given by

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{7.1-7.4}{\frac{1.2}{\sqrt{36}}}=-1.5  

P-value  

Since is a left sided test the p value would be:  

p_v =P(z  

Conclusion  

Comparing the p value and the significance level given \alpha=0.1 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the true mean is significantly lower than 7.4 minutes at 10% of significance

6 0
3 years ago
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