Ellen plans to have two children but doesn't know if they will be boy-boy, girl-girl, or boy-girl. What is the probability that
2 answers:
Answer:
Option A. 0.25
Step-by-step explanation:
Ellen plans two children but does not know if they will be boy-boy, girl-girl or boy-girl.
For the first baby to be the girl child
Probability =
Similarly probability for second baby to be the girl child will be
Now both the children are girl to probability for this event will be
= ×
=
= 0.25
Option A. 0.25 is the answer.
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Answer:
The probability that he drove the small car is 0.318.
Step-by-step explanation:
We are given that a friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work, and three-quarters of the time he takes the large car.
If he takes the small car, he usually has little trouble parking and so is at work on time with probability 0.7. If he takes the large car, he is on time to work with probability 0.5.
Let the Probability that he drives the small car = P(S) = = 0.25
Probability that he drives the large car = P(L) = = 0.75
Also, let WT = event that he is at work on time
So, Probability that he is at work on time given that he takes the small car = P(WT / S) = 0.7
Probability that he is at work on time given that he takes the large car = P(WT / L) = 0.5
Now, given that he was at work on time on a particular morning, the probability that he drove the small car is given by = P(S / WT)
We will use the concept of Bayes' Theorem for calculating above probability;
So, P(S / WT) =
=
=
= <u>0.318</u>
Hence, the required probability is 0.318.