Answer: x = - 12/9 ( the equation is negative)
Step-by-step explanation:
\frac{5}{3}x+\frac{1}{3}=13+\frac{1}{3}x+\frac{8}{3}x
\frac{5}{3}x=3x+\frac{38}{3}
\frac{5}{3}x-3x=3x+\frac{38}{3}-3x
-\frac{4}{3}x=\frac{38}{3}
3\left(-\frac{4}{3}x\right)=\frac{38\cdot \:3}{3}
-4x=38
\frac{-4x}{-4}=\frac{38}{-4}
x=-\frac{19}{2}
Answer:
- 60 percent of a number subtracted from 25
- 4 more than 2/3 of a number
Step-by-step explanation:
"60 percent of a number subtracted from 25" is a phrase that translates into 0.6 for 60% and "of a number" as 0.6x. Take this number and its subtracted from 25: 25-0.6x.
"4 more than two thirds of a number" is a phrase that translates into addition for "4 more" and multiplication with "two thirds of a number". This means 4 + 2/3y.
Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ = 
L.H.S = sin θ cos θ
so, sin θ cos θ ≠
So, the equation is not a trigonometric identity.
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<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
You can use liters, cups, etc i would suggest kiters
the Highest common factor of 130,260,390 = 130
130 = 2⋅5⋅13
260 = 2⋅2⋅5⋅13
390 = 2⋅3⋅5⋅13
Common multipliers (130; 260; 390): 2, 5, 13
Now to find the highest Common factor you need to multiply the common factors
Answer: (130 ; 260 ; 390) = 2 ∙ 5 ∙ 13 = 130
