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expeople1 [14]
3 years ago
7

HELPPPP!!!! PLEASEEE!!!

Mathematics
1 answer:
MrRissso [65]3 years ago
4 0

Answer: i believe the answer is B

Step-by-step explanation: because if p to q is true, then that means p and q are both true!

You might be interested in
Which of the following is equivalent to the inequality shown below?
VARVARA [1.3K]

Answer:

4x + 0.9 \geq 0.1 is equivalent to the inequality 40x+9 \geq 1

Step-by-step explanation:

Given inequality : 4x + 0.9 \geq 0.1

We are supposed to find Which of the following is equivalent to the inequality

4x + 0.9 \geq 0.1

\Rightarrow 4x+\frac{9}{10} \geq \frac{1}{10}

Multiply both sides by 10

\Rightarrow 4(10)x+\frac{9}{10}(10) \geq \frac{1}{10}(10)

\Rightarrow 40x+9 \geq 1

4x + 0.9 \geq 0.1 is equivalent to the inequality 40x+9 \geq 1

So, Option B is true

B) 40x+9 \geq 1

7 0
3 years ago
Keep y’all help since the tutors toooo busyyyy
astra-53 [7]
The answer to your question is C
7 0
3 years ago
How to solve this ? I am not sure pls if you know the answer answer it I really neeed it for marks
xz_007 [3.2K]

Answer:

L.S = R.S ⇒ Proved down

Step-by-step explanation:

Let us revise some rules in trigonometry

  1. sin²α + cos²α = 1
  2. sin2α = 2 sin α cosα
  3. cscα = 1/sinα

To solve the question let us find the simplest form of the right side and the left side, then show that they are equal

∵ L.S = csc2α + 1

→ By using the 3rd rule above

∴ L.S = \frac{1}{sin2\alpha} + 1

→ Change 1 to \frac{sin2\alpha}{sin2\alpha}

∴ L.S = \frac{1}{sin2\alpha} + \frac{sin2\alpha}{sin2\alpha}

→ The denominators are equal, then add the numerators

∴ L.S = \frac{1+sin2\alpha}{sin2\alpha}

∵ R. S = \frac{(sin\alpha+cos\alpha)^{2} }{sin2\alpha}

∵ (sinα + cosα)² = sin²α + 2 sinα cosα + cos²α

∴ (sinα + cosα)² = sin²α + cos²α + 2 sinα cosα

→ By using the 1st rule above, equate sin²α + cos²α by 1

∴ (sinα + cosα)² = 1 + 2 sinα cosα

→ By using the 2nd rule above, equate 2 sinα cosα by sin2α

∴ (sinα + cosα)² = 1 + sin2α

→ Substitute it in the R.S above

∴ R. S = \frac{1+sin2\alpha}{sin2\alpha}

∵ L.S = R.S

∴ csc 2α + 1 = \frac{(sin\alpha+cos\alpha)^{2} }{sin2\alpha}

4 0
3 years ago
PLEASE HELP !! (2/5) -50 POINTS-
likoan [24]

Answer:

3  -1  -2

5   1  6

Step-by-step explanation:

An augmented system has the coefficients for the variables and then the solution going across

Rewriting the equations to get them in the form

ax + by = c

-3x+y =2

3x-y =-2

5x+y = 6

The matrix is

3  -1  -2

5   1  6

4 0
3 years ago
Read 2 more answers
PLEASE HELP DUE IN 30 MINUTES
Vladimir79 [104]
<span>(a) At the end of Month 0, about how many more insects were in Pod A than Pod B? Explain.
In Pod A, the point is higher than 50, it could be 60 to 70 insects. Pod B has 20 insects. So, Pod A has at least 40 insects more than Pod B.

(b) Find and compare the growth rates of each pod. Show your work.
Pod A: (0,60) ; (1,80) ; (2,100) 
(80-60)/60 = 0.33
(100-80)/80 =  0.25

Pod B: (0,20) ; (1,44) ; (2,97)
(44-20)/20 = 1.2
(97-44)/44 = 1.2

Based on my computation, the rate of Pod A is lower than the rate of Pod B. 

(c) When does the population in Pod B exceed the population in Pod A? Explain. 
Pob B exceeds the population of Pod A at the END OF MONTH 4.

Pod A has a population of less than 200 while Pod B has a population of 469.</span>
5 0
3 years ago
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