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Nimfa-mama [501]
3 years ago
9

Simplify (square root of 2)(cube root of 2)

Mathematics
1 answer:
sineoko [7]3 years ago
8 0
\sqrt{2} \sqrt[3]{2} =

= 2^{\frac{1}{2}} \times 2^{\frac{1}{3}}

= 2^{\frac{1}{2} + \frac{1}{3}}

= 2^{\frac{3}{6} + \frac{2}{6}}

= 2^{\frac{5}{6}}

= \sqrt[6]{2^5}
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Murrr4er [49]

Choice A is the answer which is the point (1,-1)

=========================================

How I got this answer:

Plug each point into the inequality. If you get a true statement after simplifying, then that point is in the solution set and therefore a solution. Otherwise, it's not a solution.

-------------

checking choice A

plug in (x,y) = (1,-1)

y - 2x \le -3

-1 - 2(1) \le -3

-3 \le -3

This is true because -3 is equal to itself. So this is the answer.

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checking choice B

plug in (x,y) = (2,4)

y - 2x \le -3

4 - 2(2) \le -3

0 \le -3

This is false because 0 is not to the left of -3, nor is 0 equal to -3. We can cross this off the list.

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checking choice C

plug in (x,y) = (-2,3)

y - 2x \le -3

3 - 2(-2) \le -3

7 \le -3

This is false because 7 is not to the left of -3, nor is 7 equal to -3. We can cross this off the list.

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checking choice D

plug in (x,y) = (3,4)

y - 2x \le -3

4 - 2(3) \le -3

-2 \le -3

This is false because -2 is not to the left of -3, nor is -2 equal to -3. We can cross this off the list.


4 0
3 years ago
Find the midpoint of the line segment joining the points (-2, -1) and (-8,12).
SCORPION-xisa [38]

x¹ = -2 x² = -8

y¹ = -1 y² = 12

Using midpoint formula,

M = ( x¹ + x²/2 ,y¹ + ý²/2)

or,M ={ -2+(-8)/2 , (-1) +12/2}

or, =( -10/2 , 11/2)

:M = ( -5 , 11/2)

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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