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3 years ago

Simplify (square root of 2)(cube root of 2)

Mathematics

1 answer:

sineoko [7]3 years ago

8 0

$\sqrt{2} \sqrt[3]{2} =$

$= 2^{\frac{1}{2}} \times 2^{\frac{1}{3}}$

$= 2^{\frac{1}{2} + \frac{1}{3}}$

$= 2^{\frac{3}{6} + \frac{2}{6}}$

$= 2^{\frac{5}{6}}$

$= \sqrt[6]{2^5}$

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Answer:

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Step-by-step explanation:

Given $20x^{2}-30=4x$

Subtract 4x from both sides

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Since we can factor out 2 from whole equation, let's factor out 2.

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Divide with 2 on both sides

$10x^{2}-2x-15=0$

We got the quadratic equation, we can solve for x using quadratic formula.

$x=\frac{-b\pm\sqrt{b^{2}-4ac} } {2a}$

$x=\frac{2\pm\sqrt{2^{2}-4X10X(-15)} } {2X10}$

$x=\frac{2\pm\sqrt{604} }{20}$

$x=\frac{2\pm2\sqrt{151}}{20}$

$x=1.3288or-1.1288$

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