Answer:
0.6672 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 8.4 minutes
Standard Deviation, σ = 3.5 minutes
We are given that the distribution of distribution of taxi and takeoff times is a bell shaped distribution that is a normal distribution.
According to central limit theorem the sum measurement of n is normal with mean
and standard deviation 
Sample size, n = 37
Standard Deviation =

P(taxi and takeoff time will be less than 320 minutes)

Calculation the value from standard normal z table, we have,

0.6672 is the probability that for 37 jets on a given runway, total taxi and takeoff time will be less than 320 minutes.
Answer:
18....I hope thats righ
Step-by-step explanation:
2300 out of 4500 were chosen
2300 / 4500 = 0.5111
0.51 = 51%
51% is the acceptance rate.
Answer:
The answer is that c = 6
Step-by-step explanation: