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2 years ago

Find the zeros of the function.

1 answer:

3 0

F(x) = 3x³ - 12x² - 15x

1) Factor Outside: 3x( x² - 4x - 5)

Factor Inside: 3x(x + 1)(x - 5)

2) Set Equal To 0:
3x = 0
x + 1 = 0
x - 5 = 0

3) Solve:
x = 0, -1, 5

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Answer the question below

Kobotan [32]

Answer:There are 96 apples in the 12th bag.

Step-by-step explanation:

Firstly, you add the number of apples in the 11 bags.

6+28+16+27+10=87

If the mean number of apples in the 12 bags were 8, the total number of apples are 96.

Using this info, we subtract 87 from 96 to 9.

Hence, there are 9 apples in the 12th bag.

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2 years ago

Use estimation to determine which of the following expressions is greater. Explain how you got your answer. 5 × (1.9 + 3.15) and

Sonja [21]

The first one is greater. Adding 3.2 and 0.2 is easy! It's 3.4! Make that 3. Make 6.9, 7. 7×3=21. For the first one, make 1.9, 2. Then Make 3.15, 3. 5×5=25. That is why the first one is greater.

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2 years ago

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The first, third and thirteenth terms of an arithmetic sequence are the first 3 terms of a geometric sequence. If the first term

Salsk061 [2.6K]

Answer:

The first three terms of the geometry sequence would be $1$ , $5$ , and $25$ .

The sum of the first seven terms of the geometric sequence would be $127$ .

Step-by-step explanation:

Let $d$ denote the common difference of the arithmetic sequence.

Let $a_1$ denote the first term of the arithmetic sequence. The expression for the $n$ th term of this sequence (where $n\!$ is a positive whole number) would be $(a_1 + (n - 1)\, d)$ .

The question states that the first term of this arithmetic sequence is $a_1 = 1$ . Hence:

The third term of this arithmetic sequence would be $a_1 + (3 - 1)\, d = 1 + 2\, d$ .
The thirteenth term of would be $a_1 + (13 - 1)\, d = 1 + 12\, d$ .

The common ratio of a geometric sequence is ratio between consecutive terms of that sequence. Let $r$ denote the ratio of the geometric sequence in this question.

Ratio between the second term and the first term of the geometric sequence:

$\displaystyle r = \frac{1 + 2\, d}{1} = 1 + 2\, d$ .

Ratio between the third term and the second term of the geometric sequence:

$\displaystyle r = \frac{1 + 12\, d}{1 + 2\, d}$ .

Both $(1 + 2\, d)$ and $\left(\displaystyle \frac{1 + 12\, d}{1 + 2\, d}\right)$ are expressions for $r$ , the common ratio of this geometric sequence. Hence, equate these two expressions and solve for $d$ , the common difference of this arithmetic sequence.

$\displaystyle 1 + 2\, d = \frac{1 + 12\, d}{1 + 2\, d}$ .

$(1 + 2\, d)^{2} = 1 + 12\, d$ .

$d = 2$ .

Hence, the first term, the third term, and the thirteenth term of the arithmetic sequence would be $1$ , $(1 + (3 - 1) \times 2) = 5$ , and $(1 + (13 - 1) \times 2) = 25$ , respectively.

These three terms ( $1$ , $5$ , and $25$ , respectively) would correspond to the first three terms of the geometric sequence. Hence, the common ratio of this geometric sequence would be $r = 25 /5 = 5$ .

Let $a_1$ and $r$ denote the first term and the common ratio of a geometric sequence. The sum of the first $n$ terms would be:

$\displaystyle \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}$ .

For the geometric sequence in this question, $a_1 = 1$ and $r = 25 / 5 = 5$ .

Hence, the sum of the first $n = 7$ terms of this geometric sequence would be:

$\begin{aligned} & \frac{a_1 \, \left(1 - r^{n}\right)}{1 - r}\\ &= \frac{1 \times \left(1 - 2^{7}\right)}{1 - 2} \\ &= \frac{(1 - 128)}{(-1)} = 127 \end{aligned}$ .

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1 year ago

What are the x-int of the parabola graphed

Vaselesa [24]

Answer:

Step-by-step explanation:

The x-intercepts exist where y is equal to 0...which is ON the x-axis. Hence, the name "x-intercept". These are caled zeros, solutions, and roots. This parabola goes through the x-axis at x = 0 and x = 4. It is at both of these locations where the y-coordinate is 0.

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2 years ago

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Which of the following best describes the equation below? y = 5x - 15

ddd [48]

The answer is d because 3x5=15

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2 years ago

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