ΔAOB is a right angled triangle. Therefore the Pythagorean Theorem applies in this situation.
θ is the angle from a standard position of the line OA
The length of the y component is √(1-0)2 +(-3-(-3))2] =√(12+ 02) = 1 A(-3,1) to B(-3,0) which is opposite
Then the length of the x-component is √[(-3-0)2 +(0-0)2] = √(9+0)= 3 B(-3,0) to O(0,0) which is adjacent
The length of vector OA is √[(-3-0)2 + (1-0)2] = √(9+1) = √(10) A(-3,1) to O(0,0) which is the hypotenuse of the triangle
θ = 180 - α
sinθ = sin(180-α) = opposite/hypotenuse = 1/√10
cosθ = adjacent/hypotenuse = -3/√10
tanθ = opposite/adjacent = 1/-3 = -1/3
α= arcsin(1/√10) ≈ 18
θ =180 -18 ≈162
It would be 23.5 idk if your aloud to do that
or 141/6
Answer:
B
Step-by-step explanation:
17*
Answer:
log(342) - 121
Step-by-step explanation:
-121 + log(342) is a transcendental number
-115.165189262937394847783249972808918485...
Answer: C) [-1,-3,-7,-19]
Step-by-step explanation:
Range = {-2(-2) - 5, -2(-1) - 5, -2(1) - 5, -2(2) - 5} = {4 - 5, 2 - 5, -2 - 5, -4 - 5} = (-1, -3, -7, -9}
