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blagie [28]
4 years ago
14

HELP does anyone know ?

Mathematics
1 answer:
musickatia [10]4 years ago
3 0
This Simplest form is 2
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Gabe has already spent 2 minutes on the phone, and he expects to spend 1 more minute with every phone call he routes. In all, ho
wolverine [178]

Answer:

he would make 12 phone calls

Step-by-step explanation

so he talks three minutes each time he is on the phone so divide 37 by 3 to get 12.33 with the .33 repeated but you have to round down to 12 because you have to have a whole number for the calls but even if the number was 12.79 you cant round up to 13 because the number has to be over 13

8 0
4 years ago
The diagram shows several planes, lines, and points. Vertical plane P intersects horizontal plane R at line f. Vertical plane T
lbvjy [14]

Answer:

the answer is D

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Sphere A is similar to Sphere B. The scale factor of the lengths of the radii of Sphere A to Sphere B is 1 to 4. Sphere A has th
AleksAgata [21]

\bf ~\hspace{5em} \textit{ratio relations of two similar shapes} \\\\ \begin{array}{ccccllll} &\stackrel{\stackrel{ratio}{of~the}}{Sides}&\stackrel{\stackrel{ratio}{of~the}}{Areas}&\stackrel{\stackrel{ratio}{of~the}}{Volumes}\\ \cline{2-4}&\\ \cfrac{\stackrel{similar}{shape}}{\stackrel{similar}{shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array}~\hspace{6em} \cfrac{s}{s}=\cfrac{\sqrt{Area}}{\sqrt{Area}}=\cfrac{\sqrt[3]{Volume}}{\sqrt[3]{Volume}} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{\textit{sphere A}}{\textit{sphere B}}\qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}\qquad \qquad \stackrel{\stackrel{sides'}{ratio}}{\cfrac{1}{4}}=\stackrel{\stackrel{volumes'}{ratio}}{\cfrac{\sqrt[3]{288}}{\sqrt[3]{v}}}\implies \cfrac{1}{4}=\sqrt[3]{\cfrac{288}{v}}\implies \left( \cfrac{1}{4} \right)^3=\cfrac{288}{v} \\\\\\ \cfrac{1^3}{4^3}=\cfrac{288}{v}\implies \cfrac{1}{64}=\cfrac{288}{v}\implies v=18432

3 0
4 years ago
Help meeeeeeee pleaseee<br><br><br><br> thank you
Juliette [100K]

The domain and range for the following given graph or relation will be [-7,8] and [-4,3] respectively.

As per the question statement, we are given a graph which is depicted as a relation and we are supposed to tell the domain and range of the particular relation.

Now, before solving it, we need to know that domain refers to the set of possible input values and it consists of all the input values shown on the x-axis and range is the set of possible output values which are shown on the y-axis.

So, Domain : [-7,8]

And Range : [-4,3]

Hence, the domain and range for the following given graph or relation will be [-7,8] and [-4,3] respectively.

  • Domain: It refers to the set of all the possible input values and basically it consists all the input values shown on x-axis.
  • Range: It refers to the set of all the possible output values and basically it consists all the output values shown on y-axis.

To learn more about domain and range, click on the link given below:

brainly.com/question/28135761

#SPJ1

8 0
1 year ago
The roots of $3x^2 - 4x + 15 = 0$ are the same as the roots of $x^2 + bx + c = 0,$ for some constants $b$ and $c.$ Find the orde
Akimi4 [234]

we are given

quadratic equation as

3x^2-4x+15=0

now, we can find b and c from

x^2+bx+c=0

we can see that coefficient of x^2 is 1

so, we will have to make coefficient x^2 as 1

so, we divide both sides by 3

3x^2-4x+15=0

\frac{3x^2-4x+15}{3}= \frac{0}{3}

\frac{3x^2}{3}-\frac{4x}{3}+\frac{15}{3}= \frac{0}{3}

now, we can simplify it

x^2-\frac{4}{3}x+5= 0

now, we can compare it with

x^2+bx+c=0

we get

b=-\frac{4}{3}

c=5

so, we get order pair as

(b,c)=(-\frac{4}{3} , 5)..............Answer

6 0
3 years ago
Read 2 more answers
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