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Bezzdna [24]
4 years ago
15

Hello, I need help with this question (it has multiple parts. See attached.) PLEASE show ALL of your work, down to the bone! I o

nly have one chance at answering these so please don't answer if you don't know. Thanks! (Giving 100 pts, I have very limited time!)

Mathematics
1 answer:
juin [17]4 years ago
6 0

Answer:

the picture is not showing do you mind posting this question again so i can help

Step-by-step explanation:

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What is the exact value of sin(theta + beta)?
NISA [10]

Answer:  \frac{-3\sqrt{13}+4\sqrt{3}}{20}

This is the single fraction of -3*sqrt(13)+4*sqrt(3) up top all over 20.

sqrt = square root

=======================================================

Explanation:

Angle theta is between pi and 3pi/2. This places the angle in quadrant Q3 where both cosine and sine are negative

Use the pythagorean trig identity to get the following:

\sin^2 \theta + \cos^2 \theta = 1\\\\\sin^2 \theta + \left(-\frac{\sqrt{3}}{4}\right)^2 = 1\\\\\sin^2 \theta + \frac{3}{16} = 1\\\\\sin^2 \theta = 1 - \frac{3}{16}\\\\\sin^2 \theta = \frac{16}{16} - \frac{3}{16}\\\\\sin^2 \theta = \frac{16-3}{16}\\\\\sin^2 \theta = \frac{13}{16}\\\\\sin \theta = -\sqrt{\frac{13}{16}} \ \text{ ... sine is negative in Q3}\\\\\sin \theta = -\frac{\sqrt{13}}{\sqrt{16}}\\\\\sin \theta = -\frac{\sqrt{13}}{4}\\\\

Angle beta is in Q1 where sine and cosine are positive.

Draw a right triangle with legs 3 and 4. The hypotenuse is 5 through the pythagorean theorem. In other words, we have a 3-4-5 right triangle.

Since \tan \beta = \frac{3}{4}, this means \sin \beta = \frac{3}{5} \ \text{ and } \ \cos \beta = \frac{4}{5}

Use these ideas:

  • sin = opposite/hypotenuse
  • cos = adjacent/hypotenuse
  • tan = opposite/adjacent

In this case we have: opposite = 3, adjacent = 4, hypotenuse = 5.

-------------------------------------

To recap:

\cos \theta = -\frac{\sqrt{3}}{4}\\\\\sin \theta = -\frac{\sqrt{13}}{4}\\\\\cos \beta = \frac{3}{5}\\\\\sin \beta = \frac{4}{5}\\\\

They lead to this

\sin\left(\theta + \beta\right) = \sin \theta * \cos \beta - \cos \theta * \sin \beta\\\\\sin\left(\theta + \beta\right) = -\frac{\sqrt{13}}{4} * \frac{3}{5} - \left(-\frac{\sqrt{3}}{4}\right) * \frac{4}{5}\\\\\sin\left(\theta + \beta\right) = -\frac{3\sqrt{13}}{20}+\frac{4\sqrt{3}}{20}\\\\\sin\left(\theta + \beta\right) = \frac{-3\sqrt{13}+4\sqrt{3}}{20}\\\\

6 0
3 years ago
On Average, Mercury is about 57,000,000 Km from the sun, whereas Neptune is about 4.5 x 10^9 km from the sun. What is the differ
Amiraneli [1.4K]

Answer:

4.443 x10^9

Step-by-step explanation:

8 0
3 years ago
points Q and R are midpoints of the sides of triangle ABC. Triangle A B C is cut by line segment Q R. Point Q is the midpoint of
notsponge [240]

Answer:

AQ = 20 units

Step-by-step explanation:

I tried figuring in the pic below..

Similar triangles are triangles whose corresponding measures are proportional. All of their corresponding angles are also congruent. There are theorems and postulates that prove triangle similarity. Usually they requrie at least three parts of each triangle. The symbol for similarity is ~.

We have two triangles in the figure. ΔAQR and ΔABC. We will prove first that they are similar.

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3 years ago
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Which choice represents the expanded form of the expression (x- 2)3
Murljashka [212]

Answer:

(x−2)^3=x^3−6x^2+12x-8

Step-by-step explanation:

if you are talking about the binomial  (x−2)^3   you must expand then simplify. (x-2)3 you would just remove the parenthesizes and multiply -2 with 3 to get x-6 but I think you meant (x-2)^3


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3 years ago
What is equivalent to 6 exponent 8
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6^8 = 1679616 that is the answer sir
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