We know that the equation will have 23,000 in it, since that was the population in 2012. It's increasing at a rate of 2%. To show an increase, divide 2 by 100 and add a 1 on it. It'll be 1.02=102%. You'll be powering that number by however many years since 2012.
33a.
64/4 =16ppl on each side(this is a square, but a square is still a rectangle)
30/2+34/2= 15 by 17 ppl rectangle
28/2+36/2= 14 by 18 ppl rectangle
26/2+38/2= 13 by 19 ppl rectangle
24/2+40/2= 12 by 20 ppl rectangle
22/2+42/2= 11 by 21 ppl rectangle
20/2+44/2= 10 by 22 ppl rectangle
18/2+46/2= 9 by 23ppl rectangle
16/2+ 48/2 = 8 by 24 ppl rectangle
14/2+ 50/2 = 7 by 25 ppl rectangle
12/2+ 52/2 = 6 by 26 ppl rectangle
10/2 + 54/2 = 5 by 27 ppl rectangle
8/2+ 56/2 = 4 by 28 ppl rectangle
6/2+ 58/2 = 3 by 29 ppl rectangle
4/2+60/2 = 2 by 30 ppl rectangle
33b. The most appealing arrangement to me is the 16X16 square rectangle because all the sides are even.
Hope this helped!
Answer:
This is a statement not a question comment with your question
The ratio is 2 : 9
Step-by-step explanation:
Given:
The number of sports store = 4
The number of clothing store = 9
The number of jewellery stores = 5
To Find :
The ratio of number of sports stores to the total number of stores
Solution:
The ratio of number of sports stores to the total number of stores
=
The total number of stores = number of sports store + number of clothing store + number of jewellery store
The total number of stores = 4 + 9 + 5
The total number of stores = 18
Now the ratio is
= or 4 : 8
The ratio after reduction is
= or 2 : 9 or 2 to 9
Answer:
The 95% confidence interval for the population mean is between 17.9 and 20.3 years.
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 9 - 1 = 8
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.306
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 19.1 - 1.2 = 17.9 years.
The upper end of the interval is the sample mean added to M. So it is 19.1 + 1.2 = 20.3 years.
The 95% confidence interval for the population mean is between 17.9 and 20.3 years.