Question

Simplify the mathematical expressions to determine the product or quotient in scientific notation Round so the first factor goes to the tenths place.
3.3x103

3.7

2.1x10-3

(8.6x107).(9.1x1073)

(6.9x105) (4.8x10–3)

(3.7 X 102). (4.6 x 10-3)

(1.4 x 10-6). (5.7 x 108)

(3.1 x 105)-(5.3 x 10-9)

(7.3 X 102). (6.1 x 10-7)

Answer 1

Answer:

a) (This expression is written in scientific notation), b) $3.7\times 10^{0}$, c) (This expression is written in scientific notation), d) $7.8\times 10^{81}$, e) $3.3\times 10^{3}$, f) $1.7 \times 10^{0}$, g) $8.0 \times 10^{2}$, h) $1.6\times 10^{-3}$, i) $4.5\times 10^{-4}$

Step-by-step explanation:

Each expression is checked and analyzed hereafter:

a) $3.3 \times 10^{3}$ (This expression is written in scientific notation).

b) $3.7$

$3.7\times 1$

$3.7\times 10^{0}$

c) $2.1\times 10^{-3}$ (This expression is written in scientific notation).

d) $(8.6\times 10^{7})\cdot (9.1\times 10^{73})$

$(8.6)\cdot (9.1)\cdot 10^{7 + 73}$

$78.3\times 10^{80}$

$7.8\times 10^{81}$

e) $(6.9\times 10^{5})\cdot (4.8\times 10^{-3})$

$(6.9)\cdot (4.8)\times 10^{5-3}$

$33.1\times 10^{2}$

$3.3\times 10^{3}$

f) $(3.7\times 10^{2})\cdot (4.6\times 10^{-3})$

$(3.7)\cdot (4.6)\times 10^{2-3}$

$17\times 10^{-1}$

$1.7 \times 10^{0}$

g) $(1.4\times 10^{-6})\cdot (5.7\times 10^{8})$

$(1.4)\cdot (5.7)\times 10^{-6+8}$

$8.0 \times 10^{2}$

h) $(3.1\times 10^{5})\cdot (5.3\times 10^{-9})$

$(3.1)\cdot (5.3) \times 10^{5-9}$

$16.4\times 10^{-4}$

$1.6\times 10^{-3}$

i) $(7.3\times 10^{2})\times (6.1\times 10^{-7})$

$(7.3)\cdot (6.1)\times 10^{2-7}$

$44.5\times 10^{-5}$

$4.5\times 10^{-4}$