First I would change the descriptions of the numbers into expressions.
first number is n
second number is n + 6
third number is 4n (4 x n)
Then you would insert these expressions into an equation and isolate n.
n + n + 6 + 4n = 144
n + n + 4n = 144 - 6
6n = 138
n = 138/6
n = 23
Lastly, you would plug in this value into all of the expressions.
first number is 23
second number is 23 + 6 = 29
third number is 4(23) = 92
Therefore, the numbers are 23, 29, and 92.
Answer:
B. The width of the confidence interval would be smaller.
Step-by-step explanation:
By reducing the confidence level from 99% to 95%, the student assumes that there is more uncertainty about the new confidence interval than the previous one. That, being said, since the results aren't as certain, the confidence interval is widened towards a central average point because the new interval isn't as accurate.
Therefore, the answer is B. The width of the confidence interval would be smaller.
<span>2(a+b)=c
2a + 2b = c
2b = c - 2a
b = (c - 2a)/a
answer
</span><span>D. b = (c−2a)/2 ; distribute 2 to get 2a+2b, subtract 2a, then divide by 2.</span>
2.16 x 10 to the power of -4
Answer:
0.2 or 20%
Step-by-step explanation:
If the times of arrival vary uniformly, there is an equal chance of an employee reporting at any given time between 8:40 and 9:30.
The range between 8:40 and 9:30 is 50 minutes.
The range between 9:00 and 9:10 is 10 minutes.
Therefore, the probability that a randomly chosen employee reports to work between 9:00 and 9:10 is:
The probability is 0.2 or 20%.
