The molar solubility of Ba₃(PO₄)₂ is its concentration of pure substance
The correct equation for the ksp is Ksp = 6x⁵
<h3>How to determine the
equation of ksp?</h3>
Start by writing the reaction for the solution of Barium phosphate
Ba₃(PO₄)₂ ⇌3Ba²⁺ +2PO₄³⁻
Next, we make an ICE chart
Let "x" be the molar solubility of Barium phosphate
Ba₃(PO₄)₂(s) ⇌3Ba²⁺ +2PO₄³⁻
I 0 0
C +3x +2x
E 3x³ 2x²
Lastly, we write the expression for the solubility product constant (Ksp)
This is represented as:
Ksp = [3Ba²⁺] × [2PO₄³⁻]²
Ksp = 3x³ × 2x²
Evaluate the product
Ksp = 6x⁵
Hence, the correct equation for the ksp is Ksp = 6x⁵
Read more about molar solubility at:
brainly.com/question/9732001
Answer:
180= 2x+ 4x+ 3x
180= 9x
x=20
a= 40
b= 80
c= 60
40+60+80= 180 (checking answers)
Step-by-step explanation:
Answer:
The answer to the expression in simplest form is:
Step-by-step explanation:
Given the function
solving to get the simplest form
Thus, the answer to the expression in simplest form is:
Answer:
The answer would be 70.2.
Step-by-step explanation:
You just have to replace the x in the equation with a 2 because x=2.
9514 1404 393
Answer:
(a) -23
Step-by-step explanation:
The sequence is arithmetic with first term 3 and common difference -2. Then the general term is ...
an = a1 +d(n -1)
an = 3 -2(n -1)
and the 14th term is ...
a14 = 3 -2(14 -1) = 3 -2(13) = 3 -26
a14 = -23
