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Vinil7 [7]
3 years ago
9

How do you do part B of this question? Please help!!

Mathematics
1 answer:
posledela3 years ago
3 0
All i know is that the equation of a straight line  is y=mx+c .......where m= gradient and c= the y intercept
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5^(-x)+7=2x+4 This was on plato
Setler79 [48]

Answer:

Below

I hope its not too complicated

x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

Step-by-step explanation:

5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}

Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}

\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x

\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

3 0
3 years ago
What is the equation of the axis of symmetry do the quadratic function f(x) = -(x+4) (x-1)​
miv72 [106K]

9514 1404 393

Answer:

  x = -3/2

Step-by-step explanation:

The zeros of the function are the values of x that make the factors zero:

  x = -4, x = 1

The axis of symmetry is the vertical line halfway between these zeros.

  x = (-4 +1)/2 = -3/2

The equation of the axis of symmetry is x = -3/2.

8 0
3 years ago
Can someone explain how to find the answer to x​
OLga [1]

Answer:

130

Step-by-step explanation:

X is the alternate corresponding angle to 50.   50+y=180

y=130

x and y = the  same thing so 130 is the value of x

4 0
3 years ago
Read 2 more answers
Simplify: 20 sin(2x) cos(2x)
alexandr1967 [171]
Use the the double angle formula:
sin(2A)=2sin(A)cos(A)

substitute 2x for A, then
20sin(2x)cos(2x)=10(sin(2(2x))cos(2(2x))=10sin(4x)

8 0
3 years ago
(6•11)2 •2-4(-2+14)2-12 simplest terms
Ksju [112]

Answer:

\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left[-10-\left(-6\right)\right]}{\left[4+5\right]\div \left[4^2\:−\:3^2\left(4−3\right)−8\right]+12}

Step-by-step explanation:

\frac{13+\left(-3\right)^2+4\left(-3\right)+1-\left(-10-\left(-6\right)\right)}{\frac{4+5}{\left(4^2-3^2\left(4-3\right)-8\right)+12}}

8 0
3 years ago
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