Rectangular form:
z = -2.1213203-2.1213203i
Angle notation (phasor):
z = 3 ∠ -135°
Polar form:
z = 3 × (cos (-135°) + i sin (-135°))
Exponential form:
z = 3 × ei (-0.75) = 3 × ei (-3π/4)
Polar coordinates:
r = |z| = 3 ... magnitude (modulus, absolute value)
θ = arg z = -2.3561945 rad = -135° = -0.75π = -3π/4 rad ... angle (argument or phase)
Cartesian coordinates:
Cartesian form of imaginary number: z = -2.1213203-2.1213203i
Real part: x = Re z = -2.121
Imaginary part: y = Im z = -2.12132034
To solve this problem you must apply the proccedure shown below:
1. You have that the formula for calculate the area of a triangle is:
A=bh/2
Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.
bh/2=124
bh=124x2
bh=248
2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:
Base=b/2
Height=3h
3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:
A'=bh/2
(A' is the new area)
A'=(b/2)(3)/2
A'=3bh/4
4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
A'=186 units</span>²
<span>
The answer is: </span>186 units²
Answer:
10/16 (written as a fraction)
Step-by-step explanation:
Starting point
-(-2x+1)=9-14x
Solve the minus sign
2x-1=9-14x
Swap the Xs and the numbers, changing sign
2x+14x=9+1
Do calculations
16x=10
Result
x=10/16
