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Elan Coil [88]
4 years ago
8

Verify the identity sec^2(x)tan^2(x)+sec^2(x)=sec^4(x)

Mathematics
1 answer:
Natalija [7]4 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identity

tan²x + 1 = sec²x ⇒ tan²x = sec²x - 1

Consider the left side

sec²x × tan²x + sec²x

= sec²x(sec²x - 1) + sec²x ← distribute and simplify

= sec^{4} x - sec²x + sec²x

= sec^{4} x = right side ⇒ verified

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Please help me find out what the question marks are
quester [9]
Question a

g(x) times \sqrt{x-5}=\sqrt{x^2-5}
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question b
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question c
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question d
the (f*g)(x) collumn seems to have a domain of only x is greater than or equal to 0?
so maybe we squared the whole thing, ya
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ah, ya
basically
|x|=(\sqrt{x})^2=(\sqrt{x})(\sqrt{x})
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a. g(x)=\frac{\sqrt{x^3-5x^2-5x+25}}{x-5}
b. g(x)=\frac{x^2}{x+1}
c.f(x)=x^2
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Shown in the picture.

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Work out the length of the perimeter.
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According to property such triangle
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answer: 90 cm.
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