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4 years ago

What is the additive inverse of -7 -7 7 -|-7| -(-(-7)) Please help

Mathematics

2 answers:

Flauer [41]4 years ago

7 0

THE ANSWER IS 7!

What can you add to -7 to make it equal 0. It’s 7.

Daniel [21]4 years ago

5 0

The additive inverse of -7 is 7, the additive inverse of a number is when added to any number equals 0. So the additive inverse of -14=14 and 7=-7.

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What is the 32nd term of the arithmetic sequence where a1 = 12 and a13 = -60

Olin [163]

Answer:

The 32nd term of Arithmetic sequence is -174

Step-by-step explanation:

Given: $a_1=12, a_{13}=-60$

We are given two term of the Arithmetic sequence.

Formula:

$a_n=a+(n-1)d$

For $a_1=12$

$a=12$

For $a_{13}=-60$

$a+12d=-60$

Using two equation solve for a and d

$12+12d=-60$

$1+d=-5$

$d=-6$

We need to find 32nd term

$a_{32}=a+31d$

$a_{32}=12+31(-6)$

$a_{32}=12-186$

$a_{32}=-174$

Hence, The 32nd term of Arithmetic sequence is -174

5 0

3 years ago

Read 2 more answers

What is the common ratio for the geometric sequence? 32, 8, 2, 12, ... Enter your answer in the box.

mamaluj [8]

Answer:

Given sequence is not a geometric progression and there will be no common ration for this sequence.

Step-by-step explanation:

Need to determine common ration for the following geometric sequence

32, 8, 2, 12, ...

In given geometric sequence

a1 = 32, a2=8, a3=2, a4=12 ……….

Common ratio = $\frac{a_2}{a_1} =\frac{a_3}{a_2} =\frac{a_4}{a_3}$

$\frac{a_2}{a_1}=\frac{8}{32}=\frac{1}{4}$

$\frac{a_3}{a_2} =\frac{2}{8}=\frac{1}{4}$

$\frac{a_4}{a_3}=\frac{12}{2}=6$

Since $\frac{a_2}{a_1}=\frac{a_3}{a_2}\neq\frac{a_4}{a_3}$ so we can say that given sequence is not a geometric progression and there will no no common ration for this sequence.

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Answer:

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Step-by-step explanation:

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Jobisdone [24]

Answer:

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Step-by-step explanation:

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Alina [70]

Plug in 44
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