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3 years ago

List the numbers that have 30 as a multiple

1 answer:

7 0

30 has Infinite amount of multiples but a few are 60,90,120,150,180,210,240

In simpler terms multiples are what numbers go into

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xeze [42]

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4 years ago

Based on the graph below, how would you describe the curve

tatuchka [14]

Answer:

Step-by-step explanation:

The graph is a quadratic function which is forms a parabola when graphed. A parabola has a U shape. Because of this U shape, y- values repeat for different x-values. This is known as many-to-one.

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3 years ago

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LekaFEV [45]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the area of the parallelogram. Pls explain and I will give brainliest!

bazaltina [42]

Answer:

C: 697 in^2

Step-by-step explanation:

Since parallelograms have parallel lines, the 41 in and 33 in have the same area, the 17 inch and the opposite have the same area too.

You don't need any solution for this since this question already gave you the answer without needing to do any calculation except for finding the area of the parallelogram.

41 x 17 = 697in^2

3 0

3 years ago

Find the projection of the vector A = î - 2ġ + k on the vector B = 4 i - 4ſ + 7k. 15. Given the vectors A = 2 i +3 ſ +6k and B =

Gwar [14]

Answer:

Part 1)

Projection of vector A on vector B equals 19 units

Part 2)

Projection of vector B' on vector A' equals 35 units

Step-by-step explanation:

For 2 vectors A and B the projection of A on B is given by the vector dot product of vector A and B

Given

$\overrightarrow{v_{a}}=\widehat{i}-2\widehat{j}+\widehat{k}$

Similarly vector B is written as

$\overrightarrow{v_{b}}=4\widehat{i}-4\widehat{j}+7\widehat{k}$

Thus the vector dot product of the 2 vectors is obtained as

$\overrightarrow{v_{a}}\cdot \overrightarrow{v_{b}}=(\widehat{i}-2\widehat{j}+\widehat{k})\cdot (4\widehat{i}-4\widehat{j}+7\widehat{k})\\\\\overrightarrow{v_{a}}\cdot \overrightarrow{v_{b}}=1\cdot 4+2\cdot 4+1\cdot 7=19$

Part 2)

Given vector A' as

$\overrightarrow{v_{a'}}=2\widehat{i}+3\widehat{j}+6\widehat{k}$

Similarly vector B' is written as

$\overrightarrow{v_{b'}}=\widehat{i}+5\widehat{j}+3\widehat{k}$

Thus the vector dot product of the 2 vectors is obtained as

$\overrightarrow{v_{b'}}\cdot \overrightarrow{v_{a'}}=(\widehat{i}+5\widehat{j}+3\widehat{k})\cdot (2\widehat{i}+3\widehat{j}+6\widehat{k})\\\\\overrightarrow{v_{a'}}\cdot \overrightarrow{v_{b'}}=1\cdot 2+5\cdot 3+3\cdot 6=35$

7 0

4 years ago