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Salsk061 [2.6K]
3 years ago
7

Write the polynomial as a product: p2q+r2–pqr–pr

Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0

{p}^{2} q +  {r}^{2}  - pqr -  pr \\  = pq(p - r) - r(p - r) \\  = (pq - r)(p - r)

nikklg [1K]3 years ago
3 0

Answer:

(p - r)(pq - r)

Step-by-step explanation:

P = p²q + r² – pqr – pr  

Rewrite the equation in descending orders of p and increasing orders of r.

P = p²q - pqr - pr + r²

Factor the first two and the last two terms

P = pq(p - r) - r(p - r)

Remove the common factor

P = (p - r)(pq - r)

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The sum of four consecutive integers is at least 18. What's the smallest consecutive integer to make this statement true?
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Let the four consecutive integers be

x , x+1, x+2, x+3

ATQ, Their sum is 18

\sf \: x + x + 1 + x + 2 + x + 3 = 18

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\sf4x + 6 = 18

\sf4x = 18 - 6

\sf4x = 12

\boxed{ \mathfrak{x = 3}}

<h3>Now,</h3>

  • 1st number = x = 3
  • 2nd number = x+1 = 3+1 = 4
  • 3rd number = x+2 = 3+2 = 5
  • 4th number = x+3 = 3+3 = 6

<em>The four numbers are 3,4,5,6 respectively and the smallest number among them is 3</em><em>.</em><em>.</em><em>.</em><em>~</em>

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If f(x) = 3x + 5 and g(x) = x - 1, then g[f(-3)] = ?
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Answer:

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Step-by-step explanation:

I can't tell exactly what you're trying to say but if you're trying to say:

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Multiplying a positive and a negative equals a negative: (+) x (-) = (-), the use the commutative property to reorder the terms.

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