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Salsk061 [2.6K]
3 years ago
7

Write the polynomial as a product: p2q+r2–pqr–pr

Mathematics
2 answers:
Assoli18 [71]3 years ago
6 0

{p}^{2} q +  {r}^{2}  - pqr -  pr \\  = pq(p - r) - r(p - r) \\  = (pq - r)(p - r)

nikklg [1K]3 years ago
3 0

Answer:

(p - r)(pq - r)

Step-by-step explanation:

P = p²q + r² – pqr – pr  

Rewrite the equation in descending orders of p and increasing orders of r.

P = p²q - pqr - pr + r²

Factor the first two and the last two terms

P = pq(p - r) - r(p - r)

Remove the common factor

P = (p - r)(pq - r)

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\mathrm{Subtract\:each\:column\:of\:digits,\:starting\:from\:the\:right\:and\:working\:left} 

<span>We calculate </span>0-0<span>the result of which is </span>0<span> 
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