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Artist 52 [7]
3 years ago
10

If a boy scout has 3 meters of rope he cuts the rope into 3/5 m long how much rope will he have

Mathematics
1 answer:
bezimeni [28]3 years ago
7 0
1.8 or 1 4/5 hope I help make sure to thank me
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The State Board of Education has $2,183 to buy new calculators. If each calculator costs $37, how many calculators can the board
Tema [17]

Answer:

59

Step-by-step explanation:

They could buy 59

You solve this by dividing the total amount of money ($2183) by the other amount ($37) which is 59

5 0
3 years ago
If the triangles in the diagram are congruent, what is the value of x?
Natalija [7]
If shapes are congruent, then they are mathematically equal (same dimensions, angles etc.). So just locate where the angle x is on both triangles, it should have a value on or a calculable value on the other. If you provide us with the actual sheet I could walk you through it.

4 0
3 years ago
Read 2 more answers
Pls help meeeeeeeeeeeeeeeeeeeeeeeeeeee
Dennis_Churaev [7]
1/25 i don’t know if this is right but here you go
5 0
3 years ago
A manufacturer of chocolate candies uses machines to package candies as they move along a filling line. Although the packages ar
Elenna [48]

Answer:

We conclude that the mean amount packaged is equal to 8.17 ounces.

Step-by-step explanation:

We are given that in a particular sample of 50 packages, the mean amount dispensed is 8.171 ​ounces, with a sample standard deviation of 0.052 ounces.

Let \mu = <u><em>population mean amount packaged. </em></u>

So, Null Hypothesis, H_0 : \mu = 8.17 ounces    {means that the mean amount packaged is equal to 8.17 ounces}

Alternate Hypothesis, H_A : \mu\neq 8.17 ounces    {means that the mean amount packaged is different from 8.17 ounces}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                               T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~  t_n_-_1

where, \bar X = sample mean amount dispensed = 8.171 ounces

             s = sample standard deviation = 0.052 ounces

            n = sample of packages = 50

So, <u><em>the test statistics</em></u> =  \frac{8.171-8.17}{\frac{0.052}{\sqrt{50} } }  ~   t_4_9

                                    =  0.1359  

The value of t-test statistics is 0.1359.

<u>Also, the P-value of test-statistics is given by;</u>

the meaning of the​ p-value is that the p-value is the probability of obtaining a sample mean that is equal to or more extreme than 0.001 ounces away from8.17 if the null hypothesis is true.

                    P-value = P( t_4_9 > 0.136) = More than 40% {from the t-table}

Since the P-value of our test statistics is more than the level of significance of 0.01, so <u><em>we have insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the mean amount packaged is equal to 8.17 ounces.

6 0
3 years ago
Add or subtract as indicated. reduce to the lowest term. 1 1/3 + 2 1/3
Ann [662]
2 1/3 = 7/3

Both numbers should be improper fractions.

11/3 + 7/3 = 18/3

Now the fractions must be simplified
18 ÷ 3 = 6

So 11/3 + 2 1/3 = 6
6 0
3 years ago
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