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nekit [7.7K]
3 years ago
7

If 0.9x-1.3=-3.1, what is the value of x-0.8?

Mathematics
2 answers:
Butoxors [25]3 years ago
3 0
−<span>2.8
</span>Okay so "0.9x-1.3=-3.1" x=-2
 
<span><span><span>0.9x</span>−1.3</span>=<span>−3.1

</span></span>add 1.3 to both sides

<span><span><span><span>0.9x</span>−1.3</span>+1.3</span>=<span><span>−3.1</span>+1.3

</span></span><span><span>0.9x</span>=<span>−1.8

</span></span>divide both sides by 0.9

<span><span><span>0.9x/</span>0.9</span>=<span><span>−1.8/</span><span>0.9

</span></span></span>x=<span>−2</span>

So if you plug in -2 into "x-0.8" you get −2.8

<span>=<span><span>−2</span>−0.8

</span></span><span>=<span><span>−2-</span><span>0.8

</span></span></span><span>=<span>−2.8

</span></span>Hope this helps. 
Georgia [21]3 years ago
3 0
Your answer is -2.8.
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MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

<u>i (3,4) </u>

Putting in Equation 1:

6(3) + 4(4) = 34\\18+16=34\\34=34\\

Putting in Equation 2:

5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15

<u>ii. (4,2.5)</u>

Putting in Equation 1:

6(4) + 4(2.5) = 34\\24+10=34\\34=34\\

Putting in Equation 2:

5(4) - 2(2.5) = 15\\20-5 = 15\\15=15

<u>ill. (5,5)</u>

6(5) + 4(5) = 34\\30+20=34\\50\neq 34

Putting in Equation 2:

5(5) - 2(5) = 15\\25-10 = 15\\15=15

<u>iv. (3,2)</u>

6(3) + 4(2) = 34\\18+8=34\\26\neq 34

Putting in Equation 2:

5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

  • brainly.com/question/10534381
  • brainly.com/question/10538663

#LearnwithBrainly

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