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rosijanka [135]
3 years ago
14

Can someone please answer this for me? Find the measure of side a. I will give brainliest answer!

Mathematics
1 answer:
Vikentia [17]3 years ago
6 0

Answer:

6 m

Step-by-step explanation:

The sine of an angle is the ratio between the opposite side of the angle and the hypotenuse.

Hence, sin 30° = \frac{a}{c}

                         = \frac{a}{12}

                      a = 12sin30°

                      a = <u>6m</u>

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Step-by-step explanation:

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3 years ago
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Alekssandra [29.7K]

Answer:

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a) The probability of B: "the person tests positive" is the sum of:

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P(A) \cdot P(B|A)

- The probability that a person don't have the virus but the test is positive.

P(not \,A) \cdot P(B|not\,A)

Then, the probability of B: "the person tests positive" is

P(A|B)=\frac{P(B|A)}{P(B)}=\frac{P(A)\cdot P(B|A)}{P(A)\cdot P(B|A)+P(A')\cdot P(B|A')}

We have

P(A)=1/300=0.0033\\\\P(A')=1-P(A)=0.9967\\\\P(B|A)=0.8\\\\P(B|A')=0.08

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P(A|B)=\frac{P(A)\cdot P(B|A)}{P(A)\cdot P(B|A)+P(A')\cdot P(B|A')}\\\\P(A|B)=\frac{0.0033*0.8}{0.0033*0.8+0.9967*0.08}= \frac{0.00264}{0.00264+0.07974}=\frac{0.00264}{0.08238}= 0.032

The probability that a person has the virus given that they have tested positive is P(A|B)=0.032.

b) The probability P(A'|B') is

P(A'|B')=\frac{P(B'|A')\cdot P(A')}{P(B'|A')\cdot P(A')+P(B'|A)\cdot P(A)}

We have

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The probability that a person does not have the virus given that they have tested negative is P(A'|B')=0.999.

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Answer:

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