2) Type your answer h 5 2 : 2
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Write the equation of the first train: x = 12t
Write the equation of the second train: y = -20t+72, assuming the train one is at the origins when t = 0.
Now solve the equation: 12t=-20t+72,
32t = 72, then t = 2.25 hours. The two train meet after 2.25 hours.
Now the equation of the <span>pigeon is like this: x = 48t.
</span>Then for t = 2.25, we get
<span>The Hyde has flown 108 km when the trains meet.</span>
Write the equation of the second train: y = -20t+72, assuming the train one is at the origins when t = 0.
Now solve the equation: 12t=-20t+72,
32t = 72, then t = 2.25 hours. The two train meet after 2.25 hours.
Now the equation of the <span>pigeon is like this: x = 48t.
</span>Then for t = 2.25, we get
<span>The Hyde has flown 108 km when the trains meet.</span>
Width of the rectangle is 12 cm.
Solution:
The length of a rectangle is 4 cm more than its width , and the area of the rectangle is 96 cm². Find the width of the rectangle.
Given data:
Let x be width of the rectangle.
Length of the rectangle = (x + 4) cm
Area of the rectangle = 96 cm²
length × breadth = 96
Subtract 96 from both sides.
Let us factor the polynomial.
Take x common in 1st two terms and -12 common in next two terms.
Now, take (x + 8) common in both terms.
x + 8 = 0 and x - 12 = 0
x = -8 and x = 12
Dimension cannot be in negative terms, so ignore x = -8.
Width = 12 cm
Width of the rectangle is 12 cm.