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sergey [27]
3 years ago
11

2) Type your answer h 5 2 : 2​

Mathematics
1 answer:
LiRa [457]3 years ago
8 0

Answer:52.2 that should be it

Have a nice lil fun day

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How much of a radioactive kind of thorium will be left after 14,680 years if you start with
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Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

N(t)= N_{0}e^{-kt}

N(t) = amount after the time <em>t</em>

N_{0} = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t} or more simply N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }

t_{h} = time of the half-life

We know that N_{0} = 35,912, t = 14,680, and t_{h}=7,340

Plug these into the equation:

N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0
2 years ago
7. The resistance of dry human skin is about 500,000 ohms in wet, sweaty
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Answer:

Step-by-step explanation:

1000 Ohms

R = 1000

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I = 0.009

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I = V/R

R = 500000

I = 9 / 500000

I = 0.000018

5 0
3 years ago
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