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galben [10]
3 years ago
14

You try to enter your name into a cell that accepts a numeric value. What error would you receive? A. #NAME B. #VALUE C. #REF D.

##### E. #DIV

Computers and Technology
2 answers:
svp [43]3 years ago
8 0

Answer: value

Explanation:

UNO [17]3 years ago
4 0

Answer:

<h2>Option B: #VALUE</h2>

is the correct answer.

Explanation:

<h3>Reasons of #VALUE error:</h3>
  • When cells are not given the expected type of value.
  • If cells are left blank unnoticeable or for giving a null value.
  • For entering dates and other numerical data in text form.
<h3>Correcting and fixing #VALUE error:</h3>

This type of error can only be fixed by finding the cell in which there is wrong data entered and correct it.

Fixing the #VALUE error is tricky as some functions automatically ignore the data that is invalid.

<h3>EXAMPLE:</h3>
  • Suppose a cell contains the value as cost of the object and in order to make it 0, NA is inserted into the cell.
  • While making total of all the costs, that particular cell might cause #VALUE error.
  • Following image attach will help you clear the concept.

I hope it will help you!

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Write a program that prints the Grade based on the given data. 95-100: A+ 90-94: A 80-89: B+ 70-79: B 60-69: C+ 50-59: C &lt;49
mr Goodwill [35]

Answer:

The program to this question as follows:

Program:

score=int(input("Enter your percentage: ")) #input grade by user

#using conditional statement for match condition  

if 95<=score <= 100: #if value in between 95 to 100

   grade = 'A+' #assign grade

elif 90 <=score <= 94: #elif value in between 90 to 94

   grade = 'A' #assign grade

elif 80 <=score <= 89:  #elif value in between 80 to 89

   grade = 'B+' #assign grade

elif 70 <=score <= 79:  #elif value in between 70 to 79

   grade = 'B' #assign grade

elif 60 <=score <= 69:  #elif value in between 60 to 69

   grade = 'C+' #assign grade

elif 50 <=score <= 59:  #elif value in between 50 to 59

   grade = 'C' #assign grade

elif score<49 :  #elif value is less then 49

   grade = 'F' #assign grade

print (grade) #print grade

Output:

Enter your percentage: 50

C

 Explanation:

In the above python code, a variable "score" is defined, this variable is used for taking value from the user end. In the next step if-elif-else conditional statement is used, this statement is used when a group of statements is given in which one is true. The if block check score value is between 95-100 if this is true it will print A+.

In elif block if the above condition is not true, then this condition will execute, in this block, there are multiple elif block is used that can be described as follows:

  • In the first block, if the value in between 90-94. It will print A.
  • In the second block, if the value in between 80-89. It will print B+.
  • In the third block, if value in between 70-79. It will print B.
  • In the fourth block, if value in between 60-69. It will print C+.
  • In the fifth block, if value in between 50-59. It will print C.
  • In the last, if the value of the score is less then 49. It will print F.
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alina1380 [7]

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slavikrds [6]

Answer:

Following are the responses to the given question:  

Explanation:

This list is based mostly on the processor. Then you'll be ordered. An interrupt of a particular cable (wire) is produced for PC-ish CPUs (IRQ 0 - 31 for some intel processors). The bigger challenge is a lower number.

Strange factors have included a system clock, power business, 0, some reserved for use by CPU testing, serial/parallel/... ports and also some terminated/error/state/new devices requests device Thus a key touch on the keyboards could create an interrupt that was direct on old devices.

3 0
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Write the function setKthDigit(n, k, d) that takes three integers -- n, k, and d -- where n is a possibly-negative int, k is a n
liq [111]

Answer:

Explanation:

Let's do this in Python, first we need to convert the number into string in order to break it into a list of character, then we can replace the kth character with d. Finally we join all characters together, convert it to integer then output it

def setKthDigit(n, k, d):

n_string = str(n)

d_char = str(d)

n_char = [c for c in n_string]

n_char[k] = d_char

new_n_string = ''.join(n_char)

return int(new_n_string)

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