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Zinaida [17]
3 years ago
15

Christopher withdrew 30 United States dollars (USD) from an automatic teller machine in Germany. He received 24 euros (EUR). Whi

ch of these describes Christopher’s exchange rate from euros to United States dollars?
Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0

<em> 1 euro equals 1.25 dollars</em>

<h2>Explanation:</h2><h2></h2>

In this problem we know that:

  • Christopher withdrew 30 United States dollars (USD) from an automatic teller machine in Germany.
  • He received 24 euros (EUR).

So we can solve this by using unitary method:

1EUR=\frac{30EUR}{24USD} \\ \\ \boxed{1EUR=1.25USD}

So<em> 1 euro equals 1.25 dollars</em>

<em />

<h2>Learn more:</h2>

Converting units: brainly.com/question/8426032

#LearnWithBrainly

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If f(x) =4x2 - 8x - 20 and g(x) = 2x + a, find the value of a so that the y-intercept of the graph of the composite function (fo
amm1812

Answer:

The possible values are a = -2.5 or a = 4.5.

Step-by-step explanation:

Composite function:

The composite function of f(x) and g(x) is given by:

(f \circ g)(x) = f(g(x))

In this case:

f(x) = 4x^2 - 8x - 20

g(x) = 2x + a

So

(f \circ g)(x) = f(g(x)) = f(2x + a) = 4(2x + a)^2 - 8(2x + a) - 20 = 4(4x^2 + 4ax + a^2) - 16x - 8a - 20 = 16x^2 + 16ax + 4a^2 - 16x - 8a - 20 = 16x^2 +(16a-16)x + 4a^2 - 8a - 20

Value of a so that the y-intercept of the graph of the composite function (fog)(x) is (0, 25).

This means that when x = 0, f(g(x)) = 25. So

4a^2 - 8a - 20 = 25

4a^2 - 8a - 45 = 0

Solving a quadratic equation, by Bhaskara:

\Delta = (-8)^2 - 4(4)(-45) = 784

x_{1} = \frac{-(-8) + \sqrt{784}}{2*(4)} = \frac{36}{8} = 4.5

x_{2} = \frac{-(-8) - \sqrt{784}}{2*(4)} = -\frac{20}{8} = -2.5

The possible values are a = -2.5 or a = 4.5.

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3 years ago
One line passes through the points (0, 2) and (3, 4). Another line passes through the
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They are perpendicular
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Determine the x- and y- intercepts for the graph equation y = -8
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Answer:

b. No x-intercept y-intercept is (0, -8)

7 0
3 years ago
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What is the following sum? Assume x greater-than-or-equal-to 0 and y greater-than-or-equal-to 0
Free_Kalibri [48]

Answer:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, ption B is true.

Step-by-step explanation:

Given the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

solving the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

as

\sqrt{x^2y^3}=xy\sqrt{y}

2\sqrt{x^3y^4}=2xy^2\sqrt{x}

so the expression becomes

\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}

Group like terms

                                        =2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}

Add similar elements

                                        =2xy^2\sqrt{x}+2xy\sqrt{y}

Therefore, we conclude that:

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PLEASE HELP
kolbaska11 [484]

Answer:

  • a) P(x) = 32000*1.04^x
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Step-by-step explanation:

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a. <u>Formula</u>

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b. Year 5 is after 4 years, so we are looking for the value of P(4)

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