48:11 Which graphed matches the equation + 6 =

You just looked at the graph of this system of equations. Why will the lines never intercept?

Basile [38]

Answer:

Step-by-step explanation:

The have the same slope, -1, but different y-intercepts. The lines are parallel.

7 0

2 years ago

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Which figure has the same area as the parallelogram shown below? A. A triangle with a base of 4 mm and a height of 20 mm B. A tr

Arisa [49]

<h2>Answer: A trapezoid with bases of 6 mm and 14 mm and a height of 8 mm </h2>

The parallelogram in the figure has an area of $80mm^{2}$ , according to the following formula, which works for all rectangles and parallelograms:

$A_{parallelogram}=(b)(h)$ (1)

Where $b$ is the base and $h$ is the height

The area of a triangle is given by the following formula:

$A_{triangle}=\frac{1}{2}(b)(h)$ (2)

So, for option A:

$A_{triangle}=\frac{1}{2}(4mm)(20mm)=40mm^{2} \neq 80mm^{2}$

Now, the area of a trapezoid is:

$A_{trapezoid}=\frac{1}{2}(b_{1}+ b_{2})(h)$ (3)

For option B:

$A_{trapezoid}=\frac{1}{2}(15mm+25mm)(2 mm)=40mm^{2} \neq 80mm^{2}$

For option C:

$A_{trapezoid}=\frac{1}{2}(6mm+14mm)(8 mm)=80mm^{2}$ >>>>This is the correct option!

For option D:

$A_{rectangle}=(30mm)(8mm)=240mm^{2} \neq 80mm^{2}$

<h2>Therefore the correct option is C</h2>

5 0

3 years ago

Solve the given equation by using the quadratic formula: 2x^2-3x-4=0

kaheart [24]

Let's solve your equation step-by-step.2x2−3x−4=0Step 1: Use quadratic formula with a=2, b=-3, c=-4.x=−b±√b2−4ac2ax=−(−3)±√(−3)2−4(2)(−4)2(2)x=3±√414x=34+14√41 or x=34+−14√41

7 0

3 years ago

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Change this into decimal step by step plz

nika2105 [10]

Answer:

2.6

Step-by-step explanation:

3/5 ---> ?/100

100/5 ---> 20

3 20 60

-- x = -------

5 20 100

60/100 = 6/10

6/10 as a decimal is 0.6

2 + 0.6

= 2.6

<h2>Hope this helps!!</h2>

7 0

2 years ago

Find the squares of (m-1)

Alchen [17]

Answer:

Solution

verified

Verified by Toppr

m

2

−3m−1=0

m

2

−3m=1 → (1)

Third term =(

2

1

coeeficientofm)

2

(

2

1

×(−3))

2

=(

2

−3

)

2

=

4

9

Adding

4

9

to both sides of equation (1), we get

m

2

−3m+

4

9

=1+

4

9

∴ m

2

−3m+

4

9

=

4

4+9

∴ (m−

2

3

)

2

=

4

13

Taking square roots on both sides

∴ m−

2

3

=±

2

13

∴ m=

2

3

+

2

13

or m=

2

3

−

2

13

m=

2

3+

13

,

2

3−

13

are the roots of the given quadratic equation.

8 0

2 years ago

48:11 Which graphed matches the equation + 6 = - «+4)?