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3 years ago

PLEASE HELP! 17 POINTS I think it's D but I'm not sure

Mathematics

1 answer:

miss Akunina [59]3 years ago

4 0

I honestly believe its D but I'm not for sure. Sorry if i didn't help much

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Ac and bd are perpendicular bisectors of each other. find the perimeter of ADE

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Which story problem could be solved using the given equation? 1/5×2/3=m

Ksju [112]

its b. hope this helps i guess

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1. Which of the following sets of numbers could represent the lengths of the sides of an acute triangle?

statuscvo [17]

Answer:

Step-by-step explanation:

That would be an isosceles triangle, therefore, acute. All angles measure 60, therefore being acute. I'm not 100% sure though.

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3 years ago

11 points!!!!!!! and brainiest

BartSMP [9]

Answer:

B. -13

Step-by-step explanation:

this corrrect answer please mark as brainliest

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2 years ago

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How do you rationalize the numerator in this problem?

maw [93]

To solve this problem, you have to know these two special factorizations:

$x^3-y^3=(x-y)(x^2+xy+y^2)\\ x^3+y^3=(x+y)(x^2-xy+y^2)$

Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:

$\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y$

That tells us that we have:

$\frac{x-y}{h}$

So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:

$\frac{x-y}{h}*\frac{x^2+xy+y^2}{x^2+xy+y^2}=\frac{x^3-y^3}{h*(x^2+xy+y^2)}$

So, we have:

$\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}$

That is our rational expression with a rationalized numerator.

Also, you could just mutiply by:

$\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}$

Either way, our expression is rationalized.

7 0

3 years ago