Aaron is in his math class. His teacher says that class will be dismissed when the minute hand makes a 90° clockwise rotation. W
hat time will it be when the teacher dismisses the class?
4:05
3:35
3:25
3:20
3:55
4:05
3:35
3:25
3:20
3:55
1 answer:
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The values of cosine Ф and cotangent Ф are and -1
Step-by-step explanation:
When a terminal side of an angle intersect the unit circle at
point (x , y), then:
- The x-coordinate is equal to cosine the angle between the positive part of x-axis and the terminal side
- The y-coordinate is equal to sine the angle between the positive part of x-axis and the terminal side
- If x and y coordinates are positive, then the angle lies in the 1st quadrant
- If x-coordinate is negative and y-coordinate is positive, then the angle lies in the 2nd quadrant
- If x and y coordinates are negative, then the angle lies in the 3rd quadrant
- If x-coordinate is positive and y-coordinate is negative, then the angle lies in the 4th quadrant
∵ The terminal ray of angle Ф intersects the unit circle at point
- According to the 1st and 2nd notes above
∴ cosФ = x-coordinate of the point
∴ sinФ = y-coordinate of the point
∵ The x-coordinate of the point is negative
∵ They-coordinate of the point is positive
- According the the 4th note above
∴ Angle Ф lies in the 2nd quadrant
∵ x-coordinate =
∴ cosФ =
∵ y-coordinate =
∴ sinФ =
- cotФ is the reciprocal of tanФ
∵ tanФ = sinФ ÷ cosФ
∴ cotФ = cosФ ÷ sinФ
∴ cotФ = ÷
∴ cotФ = -1
The values of cosine Ф and cotangent Ф are and -1
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Answer:
See the proof below.
Step-by-step explanation:
What we need to proof is this: "Assuming X a vector space over a scalar field C. Let X= {x1,x2,....,xn} a set of vectors in X, where . If the set X is linearly dependent if and only if at least one of the vectors in X can be written as a linear combination of the other vectors"
Proof
Since we have a if and only if w need to proof the statement on the two possible ways.
If X is linearly dependent, then a vector is a linear combination
We suppose the set is linearly dependent, so then by definition we have scalars
in C such that:
And not all the scalars are equal to 0.
Since at least one constant is non zero we can assume for example that , and we have this:
We can divide by c1 since we assume that and we have this:
And as we can see the vector can be written a a linear combination of the remaining vectors
. We select v1 but we can select any vector and we get the same result.
If a vector is a linear combination, then X is linearly dependent
We assume on this case that X is a linear combination of the remaining vectors, as on the last part we can assume that we select and we have this:
For scalars defined in C. So then we have this:
So then we can conclude that the set X is linearly dependent.
And that complet the proof for this case.