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kati45 [8]
3 years ago
13

write each fraction as a sum of unit fractions. then write an equation to decompose the fraction into a different way. 4/5 and 3

/8
Mathematics
1 answer:
amid [387]3 years ago
3 0
4/5 = 1/2 +1/5 +1/10

3/8 = 1/4 +1/8

_____
It isn't clear whether you want the second decomposition to be using unit fractions, or what other restrictions may apply. It also is not clear what sort of equation is intended. Perhaps your text has an example for guidance.

4/5 = 1/2 +1/4 +1/20

3/8 = 1/3 +1/24
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Why is this not working <br><br> -2^2
BARSIC [14]

Answer:

-4

Step-by-step explanation:

(-2)^2=4 because a negative number squared is always positive

-(2)^2=-4

5 0
2 years ago
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Write a quadratic relation in the form y = ax2 + bx + c with roots 4 and - 3 and
pochemuha

Answer:

y =  2*x^2 - 2*x - 24

Step-by-step explanation:

If we have a quadratic function with roots a and b, we can write the equation for that function as:

y = f(x) = A*(x - a)*(x - b)

Where A is the leading coefficient.

In this case, we know that the roots are: 4 and -3

Then the function will be something like:

f(x) = A*(x - 4)*(x - (-3) )

f(x) = A*(x - 4)*(x + 3)

Now we need to determine the value of A.

We also know that the graph of the function passes through the point (3, -12)

This means that:

f(3) = -12

Then:

-12 = A*(3 - 4)*(3 + 3)

-12 = A*(-1)*(6)

-12 = A*(-6)

-12/-6 = A

2 = A

Then the equation is:

y = f(x) = 2*(x - 4)*(x + 3)

Now we need to write this in standard form, so we just need to expand the equation:

y = f(x) = 2*(x^2 + x*3 - x*4 - 4*3)

y = f(x) = 2*(x^2 - x - 12)

y = f(x) = 2*x^2 - 2*x - 24

Then the relation is:

y =  2*x^2 - 2*x - 24

4 0
3 years ago
Hows your day going?<br> Mines Great :D
natta225 [31]

Answer:

It sucks

Step-by-step explanation:

4 0
3 years ago
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HELP! will give brainlest or whatever its called... Triangle ABC has vertices A(–2, 3), B(0, 3), and C(–1, –1). Find the coordin
Tomtit [17]

Answers:

A ' = (-2, -3)

B ' = (0, -3)

C ' = (-1, 1)

=======================================================

Explanation:

To apply an x axis reflection, we simply change the sign of the y coordinate from positive to negative, or vice versa. The x coordinate stays as is.

Algebraically, the reflection rule used can be written as (x,y) \to (x,-y)

Applying this rule to the three given points will mean....

  • Point A = (-2, 3) becomes A ' = (-2, -3)
  • Point B = (0, 3) becomes B ' = (0, -3)
  • Point C = (-1, -1) becomes C ' = (-1, 1)

The diagram is provided below.

Side note: Any points on the x axis will stay where they are. That isn't the case here, but its for any future problem where it may come up. This only applies to x axis reflections.

4 0
4 years ago
e) Isabel’s competition,who sells books and no other products, charges a shipping fee of $1.99 per book plus a fixed fee of $3 f
inessss [21]

Answer:

It will equal 0

7 0
3 years ago
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