Question

What is 2b-7x=3(b-3)

Answer 1

Let's solve for b.

2b−7x=3(b−3)

Step 1: Add -3b to both sides.

2b−7x+−3b=3b−9+−3b

−b−7x=−9

Step 2: Add 7x to both sides.

−b−7x+7x=−9+7x

−b=7x−9

Step 3: Divide both sides by -1.

−b

−1

=

7x−9

−1

b=−7x+9

Answer:

b=−7x+9

Answer 2

First you had to subtract by two-b from both sides of equation form.

$2b-7x-2b=3(b-3)-2b$

Then simplify.

$-7x=b-9$

Next, you divide by negative seven from both sides of equation form.

$\frac{-7x}{-7}= \frac{b}{-7}- \frac{9}{-7}$

Finally, simplify by equation.

$x=-\frac{b-9}{7}$

Final answer: $\boxed{x=b-9/7}$

Hope this helps!

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-Charlie